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jrizzle
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Homework Statement
Find the allowable axial compressive load for a 3in by 2in by .25in 17 S-T aluminum-alloy angle 43in long. It acts as a pin-ended column.
Assume: Factor of safety = 2.5
Least radius of gyration, r = .43
Area = 1.19 in^2
Homework Equations
17 S-T gives modulus of elasticity of:
E = 10,600 ksi
some formulas (im sure I am missing some)
f.s. = P_u/P_all
Stress = P/A
The Attempt at a Solution
P_all = P_u/f.s = P_u/2.5
im really confused. i don't understand how there could be 3inX2inX.25in and then 43in long for one. then there is a weird area of 1.19 in^2
can someone help me with this? they didnt give a diagram either