- #1
dijkarte
- 191
- 0
Given two functions:
f:A --> B
g:B --> C
How to show that if the (g ° f) is injection, then f is injection?
I tried this:
We need to show that g(f(a)) = g(f(b)) ==> a = b holds true for all a, b in A. But there's nothing said about function g.
f:A --> B
g:B --> C
How to show that if the (g ° f) is injection, then f is injection?
I tried this:
We need to show that g(f(a)) = g(f(b)) ==> a = b holds true for all a, b in A. But there's nothing said about function g.