- #1
naspri4
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Homework Statement
Imagine a hydraulically operated dentist's chair having a mass of 190.0 kg and in it is sitting a 52.8 kg patient. The large piston beneath the chair has a diameter of 5.00 cm, whereas the small piston, moved by a pedal on which the dentist steps, has a diameter of 1.00 cm. What is the pressure in the interconnecting fluid when the dentist operates the chair?
the answer is in Mpa
Homework Equations
F=PA
The Attempt at a Solution
so there was another question right below this that asked for how much force he must exert on the smaller piston, so using F=PA i found P to equal 121.24 then i used that number with the area of the smaller piston and found the F of the smaller pistion to be 95.17N. So i assume the pressure must be right, but i don't get what the first question is asking for because although it is labeled in Mpa the answer is still wrong.
(finding pressure)
190 + 52.8 = 242.8
242.8 * 9.8 = 2389.44
2389.44= (P)(A=(pie)(2.5squared))
2389.44=(P)(19.625)
P=121.24
(finding second answer)
F=(121.24)(A=(pie)(.5squared))
F=(121.24)(.785)
F=95.17