- #1
ashina14
- 34
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I came across the question
The following equation represents two straight lines. Determine the equation of each of the two lines.
x^2+8 xy−x+16 y^2−4 y−72=0
I know we need to take common factors and the answer is
(x+4 y-9) (x+4 y+8) = 0
leading to equations y = 1/4 (-x-8) and y = (9-x)/4 but how did we get to (x+4 y-9) (x+4 y+8) = 0 in the first place?? Thanks
The following equation represents two straight lines. Determine the equation of each of the two lines.
x^2+8 xy−x+16 y^2−4 y−72=0
I know we need to take common factors and the answer is
(x+4 y-9) (x+4 y+8) = 0
leading to equations y = 1/4 (-x-8) and y = (9-x)/4 but how did we get to (x+4 y-9) (x+4 y+8) = 0 in the first place?? Thanks