- #1
cnaeger
- 2
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Hello,
I am working my way through Cal vo1 by Apostol and working the problems and was wondering if someone could assist.
The question is on pg 19 to prove theorems i.5-i.15 using axioms and theorems i.1-i.4.
Theorem i.5 states a(b-c) = ab - bc.
I started the proof but am stuck at at the point indicated below.
a(b-c) = a(b + (-c)) = ab + a(-c)
being able to represent a(-c) as -ac is not illustrated until theorem i.12.
I tried representing a(-c) as -(-a)(-c) but that did not go anywhere either due to (-a)(-c) not being illustrated until i.12 either.
Can anyone help me along with this one. This is not a homework assignment as I am a BS in EE with a minor in math. Just working my way through this book to enhance my knowledge.
Thanks,
Chad
I am working my way through Cal vo1 by Apostol and working the problems and was wondering if someone could assist.
The question is on pg 19 to prove theorems i.5-i.15 using axioms and theorems i.1-i.4.
Theorem i.5 states a(b-c) = ab - bc.
I started the proof but am stuck at at the point indicated below.
a(b-c) = a(b + (-c)) = ab + a(-c)
being able to represent a(-c) as -ac is not illustrated until theorem i.12.
I tried representing a(-c) as -(-a)(-c) but that did not go anywhere either due to (-a)(-c) not being illustrated until i.12 either.
Can anyone help me along with this one. This is not a homework assignment as I am a BS in EE with a minor in math. Just working my way through this book to enhance my knowledge.
Thanks,
Chad