- #1
david18
- 49
- 0
You record the following data Diameter/mm: 11.67, 12.67, 13.9, 12.67, 12.67, 12.66 You take the average of these values to be the diameter, but what is the percentage error in this value?
I tried working this problem out but I can't use the normal formula as it is spread over many values and there is no accepted value. I got some numbers; 17.55%, 1.5% but theyr all wrong.
W = T(x+y)/x
Where W is the weight of the stand and T is the Newton meter reading.
You measure and record the values of x, y (with a ruler) and T. The following data is recorded:
x = 12.8 cm , y = 30.2 cm, T= 2.2 N
What is the percentage uncertainty in y?
This one wants the percentage uncertainty which I'm unsure of how to find. I did try 30.25(max value) - 30.15(lowest value) / 2 = 0.05 and find it as a percentage but it turned out to be wrong...
Any help with these problems would be much appreciated.
I tried working this problem out but I can't use the normal formula as it is spread over many values and there is no accepted value. I got some numbers; 17.55%, 1.5% but theyr all wrong.
W = T(x+y)/x
Where W is the weight of the stand and T is the Newton meter reading.
You measure and record the values of x, y (with a ruler) and T. The following data is recorded:
x = 12.8 cm , y = 30.2 cm, T= 2.2 N
What is the percentage uncertainty in y?
This one wants the percentage uncertainty which I'm unsure of how to find. I did try 30.25(max value) - 30.15(lowest value) / 2 = 0.05 and find it as a percentage but it turned out to be wrong...
Any help with these problems would be much appreciated.