- #1
BillyCheung
- 10
- 0
Dear all :
I have one question about tension that is following :
The human forearm and hand can be modeled as a beam that is pivoted at one end(the elbow) and supported (by a muscle) at a short distance from the pivot. The beam(forearm) is horizontal, the muscle is vertical, the centre of mass of the beam is 15cm from the pivot, and the point of attachment of the muscle is 4 cm from the pivot. The mass of the beam is 2 kg. The pivot is frictionless.
Calculate the magnitude of the tension in the supporting muscle.
In my idea, torque = r x F = 0.15 x (2)(9.8) = 2.94Nm.
Is the tension in the supporting muscle -2.94Nm?
Thank very much. Good bye
Billy
I have one question about tension that is following :
The human forearm and hand can be modeled as a beam that is pivoted at one end(the elbow) and supported (by a muscle) at a short distance from the pivot. The beam(forearm) is horizontal, the muscle is vertical, the centre of mass of the beam is 15cm from the pivot, and the point of attachment of the muscle is 4 cm from the pivot. The mass of the beam is 2 kg. The pivot is frictionless.
Calculate the magnitude of the tension in the supporting muscle.
In my idea, torque = r x F = 0.15 x (2)(9.8) = 2.94Nm.
Is the tension in the supporting muscle -2.94Nm?
Thank very much. Good bye
Billy