iZnoGouD said:I need to make the deduction of this formula V2 = V02 +- 2g(y - y0)
Could you guys help me? this is so hard for me
The formula represents the final velocity (V2) of an object with an initial velocity (V02), undergoing constant acceleration (2g) over a vertical displacement (y-y0).
To calculate the value of V2, you first need to determine the values of V02, g, y, and y0. Then, plug these values into the formula and solve for V2.
The initial velocity (V02) and final velocity (V2) should be in meters per second (m/s), acceleration (g) should be in meters per second squared (m/s^2), and the vertical displacement (y and y0) should be in meters (m).
No, this formula is specifically used for calculating the final velocity of an object undergoing constant acceleration in a vertical direction. It cannot be applied to other types of motion, such as circular motion or variable acceleration.
This formula is derived from the equations of motion, specifically the equation v^2 = u^2 + 2as, where v is final velocity, u is initial velocity, a is acceleration, and s is displacement. By substituting a vertical displacement (y-y0) for s and using the acceleration due to gravity (g), we arrive at the formula V2 = V02 + 2g(y - y0).