
#1
Feb1014, 09:08 AM

P: 995

I am bit confused by how to approach this concept with mean field theory. As I understand a symmetry break (like a acquiring a finite magnetization) can happen if at low enough temperatures the Free energy decreases when breaking the symmetry.
Normally this temperature is found by calculating a thermal average and solving a selfconsistent equation for the critical temperature. But is it obvious, that this is the same as finding the critical temperature at which the free energy begins to decrease when breaking the symmetry? 



#2
Feb1114, 12:48 AM

Sci Advisor
P: 3,378

As far as I remember, it is usually simpler to calculate the critical temperature as that temperature where some correlation functions calculated for the normal state diverge.



Register to reply 
Related Discussions  
Chiral symmetry breaking and approximate flavour symmetry  High Energy, Nuclear, Particle Physics  8  
Symmetry breaking?  General Physics  1  
Gauge symmetry and symmetry breaking  High Energy, Nuclear, Particle Physics  2  
Symmetry Breaking  Quantum Physics  1  
Symmetry breaking, what is it?  Beyond the Standard Model  5 