Still a semi conductor?

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In summary, the students were able to determine the doping of the semiconductor from the sign observed in the Hall voltage measurement. Appropriate procedures were followed and several attempts were made after reconstructing the circuit to rectify the signs, but the experiment was unable to determine whether the samples were semi conductors.
  • #1
JamesJames
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Two students performing a Hall voltage measurement using germanium as a semiconductor reversed the magnetic field while holding the bias
current constant but did not get opposite signs for the Hall voltage. The magnitude of Hall voltage detected using a voltmeter was the same as it must be. Based on the sign observed, they could determine the doping of the semiconductor from the a) Lorentz force law and b) direction of the current which they controlled through the bias current. Appropriate procedures were followed and several attempts were made after reconstructing the circuit to rectify the signs. The experiment was attempting to illustrate the basic properties of semiconductivity. This part of the experiment attempted to calculate the Hall coefficient, type of doping (n or p) and the carrier mobility.

Part of experimental science is dealing with equipment breakdown and other
non-idealities. When this happens they had to think carefully about the extent to which their results are affected, and what they could conclude about the physics they were investigating.

Their numerical values for the Hall coefficient and carrier mobility were very close to the literature ones.

What are they able to conclude about the bandgap theory of conductors from their experiment? More specifically, were they able to say whether the samples tested are n-type or p-type semiconductors, or if they're semiconductors at all? Are their Hall voltage measurements discredited (and
why)?

Here' s what I think: The Hall voltage calculations should be valid. The agreement with literature values shows this BUT they cannot say anything about the bandgap theory..i.e. they are unable to determine whether the two samples of germanium are of different doping. They are unable, as a result, to determine whether the samples are infact semi conductors. The sign part could be due to equipmental problems but they reconstructed the circuit so I would say that this is not the problem.

Am I correct? Where and how am I messing up the interpretation of this experimental problem? With the exception of instrumental problems, what could be responsible for this sign changing flaw? :confused:

James
 
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  • #2
The wording of the experimental procedure is a little careless making this problem interpretation dependent.

I'm assuming the following interpretation : A does a Hall measurement on sample 1 with an upward B-field and bias voltage Vb. B performs the same measurement on sample 2 (contacted identically to sample 1) with a downward B-field but the same bias voltage Vb (with the same polarity). A and B measure equal Hall voltages in magnitude and sign.

If this is the question, then it's not hard to see where the change in polarity relative to a given Bz orientation comes from - the type of majority charge carrier, of course, which tells you ...

If, on the other hand - and I think this is not what the question intends - a Hall measurement is performed on a single sample while switching the direction of Bz and no polarity change is obseved, then there has to be something fishy about the experimental set-up (like, for some crazy reason there's a rectifier in the output ... or I'm missing something obvious).
 
  • #3
Thanks for the reply. I just asked around and the second erxplanation you gave is the one applicable here. The polarity did not change. Can you elaborate a bit on what you said about the rectifier? How would this affect the experimental setup? Are they still able to conclude anything about whether it is n or p type based on this?

James
 
  • #4
Anything guys? I am really lost.

James
 

1. What is a semi conductor?

A semi conductor is a material that has properties between those of a conductor and an insulator. This means it can conduct electricity to some extent, but not as well as a metal. Silicon is the most commonly used semi conductor in electronic devices.

2. How does a semi conductor work?

Semi conductors work by having a small number of free electrons and holes (positively charged vacancies) in their atomic structure. These can be manipulated by adding impurities, or "doping", to create a surplus of either electrons (n-type) or holes (p-type). This allows for the control of electric current in electronic devices.

3. What are the properties of a semi conductor?

Some key properties of semi conductors include their ability to conduct electricity when doped, their sensitivity to temperature changes, and their ability to be turned on and off (controlled) by applying voltage. They also have a band gap, which is the energy difference between the valence band and the conduction band.

4. How are semi conductors used in technology?

Semi conductors are used in a wide range of electronic devices, including transistors, diodes, solar cells, and computer chips. They are also used in sensors, such as those found in cameras and touch screens. The properties of semi conductors make them ideal for controlling and manipulating electric current in these devices.

5. What is the future of semi conductors?

The future of semi conductors is constantly evolving and developing. Some potential applications include using them in quantum computing and for creating more efficient solar cells. Research is also being done on using different materials, such as carbon-based materials, as semi conductors. As technology advances, the possibilities for semi conductors will continue to expand.

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