Automorphism I don't understand

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An automorphism of a graph G is defined as a permutation of its vertex set that preserves the edge structure, meaning that if {a,b} is an edge, then {p(a), p(b)} must also be an edge. This concept is closely related to isomorphisms, as an automorphism can be viewed as an isomorphism where the domain and codomain are the same graph. The discussion clarifies that while all automorphisms are isomorphisms, not all isomorphisms are automorphisms. Understanding this distinction is crucial for grasping the properties of graphs in mathematical contexts. The relationship between automorphisms and isomorphisms highlights the structural symmetries within graphs.
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A permutation p of the vertex set of a graph G with the property that {a,b} is an edge if and only if {p(a), p(b)} is an dege, is called an automorphism of G. Is this right? this sounds isomorphism to me.
 
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An automorphism is an isomorphism whose domain equals its codomain. So you know the general notion of an isomorphism f : G -> H. Well an isomorphism f : G -> G is called an automorphism of G.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...
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