Theorem 10: Prime Counting Function and Loglog x

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The discussion centers on Theorem 10 from Hardy's number theory book, which states that the prime counting function pi[x] is greater than or equal to loglog x. Participants express confusion over the compact arguments presented in the text, particularly regarding the derivation of the inequality p_{n} < 2^{2^n}. Clarification is sought on how this step is crucial, with the understanding that pi(x) is an increasing function and that pi(p_n) equals n. The conversation also touches on Bertrand's postulate, noting that the derived bound for p_n is simpler to prove and follows from a modification of Euclid's proof of the infinitude of primes. Overall, the thread highlights the complexities involved in understanding the theorem's implications and proofs.
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I am going through Hardy's book on number theory.The following theorem I do not understand.

theorem 10: pi[x] >= loglog x
where pi[x] is the prime counting function
and >= stands for greater than or equal to

The arguments written in the book are very compact.please help .
 
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Do you follow any of it?

Do you understand how they derived p_{n}&lt;2^{2^n} ?

this is an important step. The rest just follows from pi(x) being increasing, and also \pi(p_n)=n which they use but don't explicitly mention.
 
Bertrand's postulate?
 
Nope! the bound of p_n above is much weaker than Bertrand's will give you. It's correspondingly simpler to prove though, it follows from a slight adaptation of Euclid's proof there are infinitely many primes (in case anyone who hasn't seen it wants to give it a stab)
 
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