Exploring Centripetal Force: Lab Results & Proportionality Statements

In summary, a lab on centripetal force involving swinging a mass on a string over our heads was conducted. The frequency, mass, and radius were adjusted and data was collected to graph the relationship between force centripetal, mass, frequency squared, and radius. The experiment showed that as mass and frequency increase, force centripetal also increases, but there was confusion about the relationship between force centripetal and radius. Through further analysis, it was determined that the equation Fc = 4pi^2rf^2 (or Fc = mw^2r) accurately represents the relationship. Additionally, the final proportionality statement for all three variables was found to be Fc is proportional to (m^0.816)(
  • #1
Vesper89
6
0
We're doing a lab on centripetal force where we swing a mass on a string over our heads. The string passes through a glass sleeve and has masses suspended at the bottom of the string like this...http://www.batesville.k12.in.us/Physics/PhyNet/Mechanics/Circular%20Motion/labs/cf_and_speed.htm"
Although the experiment is not the same.

We had to adjust the radius and mass and then calculate the frequency for each trial. We then had to graph the relation between Force centripetal and the mass, Fc and frequency squared and finally Fc vs Radius. We then have to come up with proportionality statements for each and then combine each statement into one proportionality statement that relates all three.

We have the first two...
1) As mass increases Fc increases
2) As frequency increases Fc increases
But we are stuck at the radius. Our data shows that at a constant frequency and mass, then as the radius increases, Fc also increases (which makes sense since a greater velocity would be required to maintain the frequency of a string with a greater radius). But various internet sources state that as the radius increases, the force decreases?? Is this just because they are not taking frequency into account? Which is it?

Finally what should the radius proportionality statement and the final proportionality statement look like? Bear in mind the equation Fc= 4pi(2)rf(2)

Thanks for any help,
Andrew
 
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  • #2
There are two equivalent expressions for centripetal force:
[tex]F_c = m v^2/r[/tex]
or
[tex]F_c = m \omega^2 r [/tex]

Since [itex] v = \omega r[/itex], the two expressions are equivalent. ([itex]\omega[/itex] is the angular speed; it equals the frequency times [itex]2 \pi[/itex].)

Since you are holding the frequency constant while you vary the radius, your results will follow the 2nd equation. If you held the speed constant as you varied the radius, your results would be described by the first equation.
 
  • #3
Really! We did this lab last week too. How cool!

Anyways what we foun was that Fc is directly proportional to Radius to the power of n if both mass and frequency are kept constant.

For the constant frequency you have to square the frequency and then plot a graphy of squared frequency and Fc. (it shouls pass throught the orgin since when frequency square is zero so is Fc). Using this graph determine 4 values of freq. sqr. for contant Fc. Then find radis required for contant frequency. Then plot a graph of Fc vs. radius and use the graph to find relationship, or use log eqn.
 
  • #4
For the final proportianality satement combine all the above proportianality. ours lookes a bit like this:
Fc is proportional to (m to the power of 0.816)(R to the power of 1.07)(freq. to the power of 1.31)
The above is just:
mR(f(squared))
 
  • #5
I think that helped. I have the equation Fc=4п²rf² (which is the same as Fc=mw²r). I think the main reason we were having difficulty was because our data isn't very accurate. Anyway, thanks.
 

1. How does centripetal force work in a lab setting?

Centripetal force is a force that acts on an object moving in a circular path, pulling it towards the center of the circle. In a lab, this force can be created by spinning an object around a fixed axis or by rotating a container of liquid at a constant speed.

2. What are the applications of studying centripetal force in a lab?

Studying centripetal force in a lab can have various applications, such as understanding the motion of planets and satellites, designing and testing amusement park rides, and analyzing the behavior of blood cells in a centrifuge.

3. What are the factors that affect centripetal force in a lab experiment?

The factors that affect centripetal force in a lab experiment include the mass of the object, the speed of rotation, and the distance from the center of rotation. These factors can be adjusted to observe their impact on the force.

4. How is centripetal force measured in a lab?

Centripetal force can be measured in a lab using a force sensor or a spring scale. The force acting on the object moving in a circular path can be measured and compared to the calculated centripetal force using the formula F = mv²/r, where m is the mass, v is the speed, and r is the radius of the circle.

5. What are some common misconceptions about centripetal force in a lab?

One common misconception is that centripetal force is a separate force acting on an object, when in reality it is the result of other forces, such as gravity or tension. Another misconception is that centripetal force always points towards the center of rotation, when in fact it can change direction depending on the motion of the object.

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