Resonant length and wavelength of sound?

AI Thread Summary
The discussion focuses on determining the relationship between resonant length and wavelength using a resonant tube filled with water and a tuning fork. The wavelength is calculated by dividing the speed of sound in room temperature by the frequency of the tuning fork, which is 1024 Hz. The resonant length corresponds to the wavelength multiplied by the number of half-wavelengths that fit within the tube. For example, at the first resonant point, the resonant length of 7.8 cm correlates with a wavelength of 0.23, indicating multiple half-wavelengths fit in the tube. Understanding this relationship is crucial for analyzing sound resonance in the experiment.
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hi we did a lab with a resonant tube filled with water
we're supposed to figure out the relationship between the resonant length and the wavelength.
what we did was we filled up the resonant tube with water then put a tuning fork above it and found where that same sound was made.
Here is an example:
frequency of the tuning fork = 1024
1st resonant point:
resonant length: 7.8cm
0.23 ( lamda )
2nd resonant point: 24.5cm
0.72
and so on...

we figured out the resonant length in lamda by finding out velocity of sound in room temperature and finding out lamda by v/f
then resonant length (lamda) was figured out by res. length (cm) / wavelength (lamda)

now i have to figure out the relationship between the resonant length and the wavelength. first is the wavelength here referring to the wavelength figured out by v/f or lamda for resonant length?? is there a relation between the resonant length of the tube and the lamda resonant length?
can someone please help me figure out any kind of relationship here??
 
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The relationship between the resonant length and the wavelength is that the wavelength is equal to the speed of sound in the medium (in this case, room temperature) divided by the frequency of the tuning fork (1024). The resonant length is equal to the wavelength multiplied by the number of half-wavelengths that fit into the tube. So, for example, for the first resonant point, since the wavelength is 0.23, and the resonant length was 7.8 cm, 0.23*7.8 = 1.814, so there were 8 half-wavelengths in the tube.
 
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