Analytical Chemistry involving buffer

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To create a buffer solution with a pH of 3.37 using 0.200M HCl and 250.0ml of 0.300M sodium mandelate, the dissociation of HCl must be considered as it fully dissociates. The pH equation pH = pKa + log [A-/HA] is applicable, but the pKa value for sodium mandelate needs to be known for accurate calculations. The discussion emphasizes that HCl will protonate some of the sodium mandelate, and this process should be treated as stoichiometric. Understanding the relationship between the concentrations of the acid and its conjugate base is crucial for achieving the desired pH. Accurate calculations will depend on knowing the pKa of the buffer system involved.
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Homework Statement



What volume of 0.200M HCl must be added to 250.0ml of 0.300M sodium mandelate to produce a buffer solution with a pH of 3.37?


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The Attempt at a Solution



For 2 and 3, can I use the equation pH = pKa + log [A-/HA]? but for HCl isn't that 100% disassociation? How can we use that if the Ka is not a given value for HCl?

Thanks.
 
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You are correct... Think of the HCl being used only to protonate a portion of the sodium mandelate.
 
And assume this protonation is stoichiometric.
 
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