maximum height reached by a ball using work-energy theorem


by ph123
Tags: ball, height, maximum, reached, theorem, workenergy
ph123
ph123 is offline
#1
Mar13-07, 05:39 PM
P: 41
A ball is launched with initial speed v from ground level up a frictionless slope. The slope makes an angle theta with the horizontal. Using conservation of energy, find the maximum vertical height hmax to which the ball will climb. Express your answer in terms of v, g, and theta. You may or may not use all of these variables in your answer.



The max height of a body is given by

mgh = 0.5mv^2
gh = 0.5v^2
h = v^2/2g

since the ball is at an angle, and at max height there is zero velocity in the y direction, the only velocity is that in the x-direction, or vcos(theta).

v^2cos(theta)/2g = hmax

but that isn't right. Anyone have any ideas?



3. The attempt at a solution
Phys.Org News Partner Science news on Phys.org
SensaBubble: It's a bubble, but not as we know it (w/ video)
The hemihelix: Scientists discover a new shape using rubber bands (w/ video)
Microbes provide insights into evolution of human language
Dick
Dick is offline
#2
Mar13-07, 05:52 PM
Sci Advisor
HW Helper
Thanks
P: 25,175
Are you SURE the angle of the ramp has anything to do with it? Think about kinetic and potential energy. And why do you think there is any x velocity when the ball reaches it's highest point?
zenmaster99
zenmaster99 is offline
#3
Mar13-07, 05:56 PM
P: 20
Dick beat me to the punch: Energies are scalars---they don't have a direction associated with them. There is no such thing as "kinetic energy in the [tex]\hat x[/tex] direction.

ZM

ph123
ph123 is offline
#4
Mar13-07, 05:59 PM
P: 41

maximum height reached by a ball using work-energy theorem


well, why bother giving me an angle if it has nothing to do with the answer? if i threw the ball at 89 degrees off the roof it would attain a greater max height than if i threw it 45 degrees off the top of the building.
Dick
Dick is offline
#5
Mar13-07, 06:01 PM
Sci Advisor
HW Helper
Thanks
P: 25,175
The problem says, "You may or may not use all of these variables in your answer." Being on a ramp is different from just flying. When the ball stops at the top, it REALLY stops.
ph123
ph123 is offline
#6
Mar13-07, 06:05 PM
P: 41
v^2/2g, then.

but what if was throwing the ball off the roof of the building. wouldn't the angle be important then?
Dick
Dick is offline
#7
Mar13-07, 06:06 PM
Sci Advisor
HW Helper
Thanks
P: 25,175
Yes. Very important.
ph123
ph123 is offline
#8
Mar13-07, 06:08 PM
P: 41
so, then, imagine i do throw the ball off the top then. Would my wrong answer from my first post, v^2cos(theta)/2g, be the max height in that case?
Dick
Dick is offline
#9
Mar13-07, 06:18 PM
Sci Advisor
HW Helper
Thanks
P: 25,175
Nope. It's not that simple. As zenmaster said, you can't split the kinetic energy into components. You need to split the velocity. And cos is the wrong trig function. The vertical component is given by a sin.
zenmaster99
zenmaster99 is offline
#10
Mar13-07, 07:44 PM
P: 20
Quote Quote by ph123 View Post
well, why bother giving me an angle if it has nothing to do with the answer? if i threw the ball at 89 degrees off the roof it would attain a greater max height than if i threw it 45 degrees off the top of the building.
That's possibly true, but for the wrong reason.

If we neglect the ramp entirely, and just throw the ball, then the ball never stops in the [tex]\hat x[/tex] direction. It never dumps all of its kinetic energy into potential energy. And that's the clue here: In this problem, the ball can stop at the top of the ramp. Neglecting friction, the only place it can put that kinetic energy is into potential energy.

Depending on how much velocity is lost attaining maximum height, the 45 degree trajectory could go higher than the 89 degree trajectory.

Make sense?

ZM


Register to reply

Related Discussions
Find the maximum height and the range of the ball. Introductory Physics Homework 5
Finding the max height of a ball launched as a projectile using work-energy Introductory Physics Homework 3
Ball height reached when rolling on inclines - rough or smooth Advanced Physics Homework 13
Maximum work theorem Classical Physics 0
Theorem of maximum work (Thermo) Introductory Physics Homework 1