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Spring constant problem

by lilmul123
Tags: constant, spring
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lilmul123
#1
Jun4-07, 02:21 PM
P: 40
This is my first time here! Thanks for the help in advance.

The staples inside a stapler are kept in place
by a spring with a relaxed length of 0.115 m.
If the spring constant is 45.0 N/m, how
much elastic potential energy is stored in the
spring when its length is 0.145 m? Answer in
units of J.

I know I have to use F=kx (maybe), but what's confusing me is the potential energy part. How do I fit that into finding the answer?
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Amith2006
#2
Jun4-07, 02:30 PM
P: 421
elastic P.E = work done to compress =integral of [(F)x(dx)] between the limits 0.145 and 0.115
Dick
#3
Jun4-07, 02:32 PM
Sci Advisor
HW Helper
Thanks
P: 25,235
If you haven't done calculus, the result Amith2006 is pointing you toward can be written PE=(1/2)*k*x^2, where x is the displacement from equilibrium.

lilmul123
#4
Jun4-07, 02:35 PM
P: 40
Spring constant problem

Yeah, I've done calculus, but thank you both!


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