
#1
Jun407, 02:21 PM

P: 40

This is my first time here! Thanks for the help in advance.
The staples inside a stapler are kept in place by a spring with a relaxed length of 0.115 m. If the spring constant is 45.0 N/m, how much elastic potential energy is stored in the spring when its length is 0.145 m? Answer in units of J. I know I have to use F=kx (maybe), but what's confusing me is the potential energy part. How do I fit that into finding the answer? 



#2
Jun407, 02:30 PM

P: 424

elastic P.E = work done to compress =integral of [(F)x(dx)] between the limits 0.145 and 0.115




#3
Jun407, 02:32 PM

Sci Advisor
HW Helper
Thanks
P: 25,165

If you haven't done calculus, the result Amith2006 is pointing you toward can be written PE=(1/2)*k*x^2, where x is the displacement from equilibrium.




#4
Jun407, 02:35 PM

P: 40

Spring constant problem
Yeah, I've done calculus, but thank you both!



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