# Spring constant problem

by lilmul123
Tags: constant, spring
 P: 40 This is my first time here! Thanks for the help in advance. The staples inside a stapler are kept in place by a spring with a relaxed length of 0.115 m. If the spring constant is 45.0 N/m, how much elastic potential energy is stored in the spring when its length is 0.145 m? Answer in units of J. I know I have to use F=kx (maybe), but what's confusing me is the potential energy part. How do I fit that into finding the answer?
 P: 424 elastic P.E = work done to compress =integral of [(F)x(dx)] between the limits 0.145 and 0.115
 HW Helper Sci Advisor Thanks P: 24,460 If you haven't done calculus, the result Amith2006 is pointing you toward can be written PE=(1/2)*k*x^2, where x is the displacement from equilibrium.
P: 40

## Spring constant problem

Yeah, I've done calculus, but thank you both!

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