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Same old twin paradox

 
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Jun27-07, 07:47 AM   #35
 

Same old twin paradox


Quote by Janus View Post
They already exist:
[tex]t = \frac{c}{a} sinh \left( \frac{aT}{c} \right) [/tex]

[tex]T = \frac{c}{a} sinh^{-1} \left( \frac{at}{c} \right) [/tex]

They are derived from the standard Relativity equations.
Could you please give me an explanation of notations used and if possible,a link to derivations.
And please explain me how somebody knows,who is accelerating?
Jun27-07, 10:17 AM   #36
 
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Quote by newTonn View Post
Could you please give me an explanation of notations used and if possible,a link to derivations.
The notation is explained on the relativistic rocket page, not sure where you'd find a derivation.
Quote by newTonn
And please explain me how somebody knows,who is accelerating?
In flat spacetime (no sources of gravity), the accelerating individual will feel G-forces in the direction of acceleration, the inertial individual will feel weightless.
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