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idempotent proof |
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| Oct15-07, 11:35 AM | #1 |
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idempotent proof
If A and B are idempotent(A=A^2) and AB=BA, prove that AB is idempotent.
this is what i got so far. AB=BA AB=B^(2)A^(2) AB=(BA)^(2) this is where I get stuck. Do A and B have inverses? if so, why? should I be thinking about inverses or is there another way of approaching this problem? |
| Oct15-07, 12:37 PM | #2 |
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| Oct15-07, 01:27 PM | #3 |
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can you just switch the B and A from ABAB to get AABB?
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| Oct15-07, 01:53 PM | #4 |
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idempotent proof
ABAB = A(BA)B = A(AB)B = AABB. Is that OK ?
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| Oct15-07, 02:02 PM | #5 |
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i doubt you can switch those matrices b/c youre multiplying the two of them. This has got be wrong. there has to be a different way to get what im trying to get.
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| Oct15-07, 02:31 PM | #6 |
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| Oct15-07, 02:31 PM | #7 |
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| Oct15-07, 02:32 PM | #8 |
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As has been pointed out THEY COMMUTE! But that isn't why I post. I want to point out that only in the trivial case can an idempotent be invertible.
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| Oct15-07, 02:42 PM | #9 |
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so if i start the proof off with AB=BA then I can use AB=BA later on in the proof I started off with in the firszt place?
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| Oct15-07, 03:02 PM | #10 |
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