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[SOLVED] Average Potential Difference

 
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Apr22-08, 08:18 PM   #1
 

[SOLVED] Average Potential Difference


1. The problem statement, all variables and given/known data
The voltage across the terminals of an ac power supply varies with time according to V=V_0\cos(\omega t). The voltage amplitude is V_0 = 46.0 V

From the prior question, I already figured out that the root-mean-square potential difference is 32.5. V

Question What is the average potential difference V_{{\rm a}{\rm v}} between the two terminals of the power supply?


2. Relevant equations

[tex]V_{rms}=V/\sqrt{2}[/tex]
[tex]V_{rms}=Vcos(\omega*t+\varphi)[/tex]


3. The attempt at a solution

At first I thought that the average and the rms was the same thing, but now I can't figure it out. Does it involve finding current?
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Apr22-08, 10:06 PM   #2
 
Quote by ttiger2k7 View Post

At first I thought that the average and the rms was the same thing, but now I can't figure it out. Does it involve finding current?
The average is just like the rms, except you don't square before integrating and you do not take a square root afterwards. It does noet involve finding current
Apr22-08, 10:20 PM   #3
 
Hm, I don't understand. Where would you be integrating?
Apr22-08, 10:24 PM   #4
 

[SOLVED] Average Potential Difference


Quote by ttiger2k7 View Post
Hm, I don't understand. Where would you be integrating?
when calculating the average. How did you calculate V_rms? You integrate over one full period of the AC and divide by the length of the period.
Apr22-08, 10:35 PM   #5
 
All I did to calculate V_rms was taking V divided by square root of 2, since for any sinusoidally varying quantity the rms value is always [tex]\frac{1}{\sqrt{2}}[/tex] the value. I didn't integrate at all.
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