Basketball Projectile Motion Problem

AI Thread Summary
A basketball player, standing 2.00 meters tall and 10.0 meters from a basket at 3.05 meters high, needs to determine the initial speed required to make a successful shot at a 40-degree angle. The player has set up equations for horizontal and vertical motion but is struggling to solve for the initial velocity (vi) due to the resulting quadratic equation. A suggestion was made to ensure no acceleration is considered in the x-direction and to treat the x and y components of speed as vector additions. Additionally, advice was provided on formatting equations properly using coding techniques or LaTex for clarity. The discussion focuses on solving the projectile motion problem effectively.
Jeff231
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Homework Statement



A basketball player who is 2.00[m] tall is standing on the floor 10.0 [m] from the basket, as in the figure. If he shoots the ball at 40.0degrees angle with the horizontal, at what initial speed must he throw so that it goes through the hoob without striking the backboard? The basket height is 3.05[m].

physicsc.jpg



Homework Equations



xf = xi + vit + 1/2at^2
yf= yi +vit + 1/2at^2

The Attempt at a Solution



I used the yf equation to come up with an equation that has vi and t as the variables. Then I used the xf equation and solved for t. Then I plugged in that t into the yf equation. It comes out to a pretty large quadratic equation:

-4.9 (10/vi(sin40))^2 + (vi(cos40))(10/vi(sin40)) - 1.05 = 0

Now I'm having trouble finding vi. I'm pretty sure I did everything right, but can someone help me figure out how to solve for vi?

Also, how do you make it so the quations come up looking normal instead of typing it here, it's formatted different? Is that a website you type it in and link here? Thanks!

-Jeff
 
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Jeff231 said:

Homework Statement



A basketball player who is 2.00[m] tall is standing on the floor 10.0 [m] from the basket, as in the figure. If he shoots the ball at 40.0degrees angle with the horizontal, at what initial speed must he throw so that it goes through the hoob without striking the backboard? The basket height is 3.05[m].

Homework Equations



xf = xi + vit + 1/2at2
yf = yi + vit + 1/2at2

The Attempt at a Solution



I used the yf equation to come up with an equation that has vi and t as the variables. Then I used the xf equation and solved for t. Then I plugged in that t into the yf equation. It comes out to a pretty large quadratic equation:

-4.9 (10/vi(sin40))^2 + (vi(cos40))(10/vi(sin40)) - 1.05 = 0

Now I'm having trouble finding vi. I'm pretty sure I did everything right, but can someone help me figure out how to solve for vi?

Also, how do you make it so the quations come up looking normal instead of typing it here, it's formatted different? Is that a website you type it in and link here? Thanks!

-Jeff

First of all I hope you didn't show any acceleration in the x direction. I haven't checked what you did, but that term is 0 for Vx.

As to figuring combined x,y speed remember that the x and y components of speed add like vectors.

As to the superscripting and subscripting, I modified your Relevant Equations to show you how to code it. You can also use TEX (LaTex) but that is a more complicated tutorial. If you open up some of the posts with formulas, if you can make a 10 m jumpshot, that won't be so hard.
 
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