
#1
Oct508, 10:11 PM

P: 191

1. The problem statement, all variables and given/known data
A physics student in a hot air balloon ascends vertically at a constant speed. Consider the following four forces. that arise in this question. F1 = the weight of the hot air balloon F2 = the weight of the student F3 = the force of the student pulling on the earth F4 = the force of the hot air balloon pulling on the student Which two of these forces form an "actionreaction" pair that obeys Newton's third law? a)F1 and F2 b)F2 and F3 c)F1 and F3 d)F2 and F4 e)F3 and F4 3. The attempt at a solution I think it's d) because gravity is pulling the student downwards while the hot air balloon is exerting the same force in the opposite direction, keeping the student in the basket. Is this a correct assumption? 



#2
Oct508, 10:24 PM

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No, this is not the 3rd law. Look up its definition in regard to the 'actionreaction' pair. Essentially, if A exerts a force on B, then B exerts an equal but opposite force on A.




#3
Oct508, 10:41 PM

P: 191

Do you mean the question does not pertain to the third law or my answer?




#4
Oct608, 08:00 AM

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Newton's Third Law 



#5
Oct608, 08:06 AM

P: 191

So, would it then be b)?




#7
Oct608, 08:56 AM

P: 191

because the earth is pulling on the student while is is pushing away from the earth at an equal and opposite direction?




#8
Oct608, 09:39 AM

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#9
Oct608, 03:28 PM

P: 191

Ah, I see. Thanks for your help PhanthomJay!!



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