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Surface Integral of a Sphere (non-divergence)

by Wildcat04
Tags: integral, nondivergence, sphere, surface
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Wildcat04
#1
Nov11-08, 08:20 PM
P: 34
1. The problem statement, all variables and given/known data

Evaluate: [tex]\int[/tex][tex]\int[/tex]G(r)dA

Where G = z
S: x2 + y2 + z2 = 9 [tex]z \geq 0[/tex]

2. Relevant equations

Parameterization
x = r sinu cosv
y = r sinu sin v
z = r cos u


3. The attempt at a solution


r(u,v) = (r sinu cosv)i + (r sinu sinv)j + (r cosu)k
ru = (r cosu cosv)i + (-r cos u sinv)j + (-r sinu)k
rv = (-r sinu sinv)i + (r sinu cosv)j + 0k

dA = |ru x rv|

I am not sure if I am approaching this correctly or if I am way off base. My next step was to complete the dot product of z with dA but this does not seem right and I can't find any good examples in my text.

Thank you in advance.
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Dick
#2
Nov11-08, 10:09 PM
Sci Advisor
HW Helper
Thanks
P: 25,251
You are doing it ok. There's a simpler way to get dA. You know that dV in spherical coordinates is just r^2*sin(u)*du*dv*dr, right? dA over a sphere is just that without the dr. But you should get the same thing by finding the norm of your cross product.
HallsofIvy
#3
Nov12-08, 04:11 AM
Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 39,293
r= 3 in this problem and you don't use "the dot product of z with dA" because neither is a vector! Just multiply and integrate.

Wildcat04
#4
Nov12-08, 11:52 AM
P: 34
Surface Integral of a Sphere (non-divergence)

Thank you very much for the help! I believe that I have figured it out now.


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