How Does the Timing of CLK Influence J-K Flip Flop Waveforms?

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The timing of the CLK in a J-K flip-flop is crucial for understanding its waveform behavior, as transitions occur only on the rising edge of the clock signal. When J=K=0 and the CLK is high, the output Q remains unchanged, reflecting the current state of the flip-flop. In contrast, when J=K=1 at the rising clock edge, the flip-flop toggles its state. The confusion often arises from not recognizing that the flip-flop's state is stable until the next clock edge. Understanding these timing relationships is essential for grasping how J-K flip-flops function.
bec13
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I understand that the truth table involved, and how it works, but i don't get the timing of the diagrams. I've looked on numerous internet sites and through many books but i still don't understand how when J=K=0 and CLK= up, with Q having no change, that the out put (Q) is up, when the others are down. My confusion continues throughout the entire waveform, mostly i believe, as i do not understand the timings of the CLK.

Is there a set time of CLK between each of the inputs? Basically, i would just like a straight answer to explain to me how the waveform works:)
 
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bec13 said:
I understand that the truth table involved, and how it works, but i don't get the timing of the diagrams. I've looked on numerous internet sites and through many books but i still don't understand how when J=K=0 and CLK= up, with Q having no change, that the out put (Q) is up, when the others are down. My confusion continues throughout the entire waveform, mostly i believe, as i do not understand the timings of the CLK.

Is there a set time of CLK between each of the inputs? Basically, i would just like a straight answer to explain to me how the waveform works:)

http://en.wikipedia.org/wiki/Flip-flop_(electronics)#JK_flip-flop

Note that transitions in the flip-flop state occur only on the rising clock edge, not when the clock is stable. Additionally, the particular case you ask about, J=K=0 with a rising clock edge (and not a HIGH clock) holds the present state of the flip-flop. J=K=1 with a rising clock edge causes the flip-flop state to toggle. Why? That's the defined function of the J-K flip-flop.
 
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