- #1
esvion
- 19
- 0
The force of attraction formula between two charges is
[tex]\frac{(k)(e1)(e2)}{r^2}[/tex]
How does the inverse of r2 fit into the equation? I understand the concept of how distance would need to be the inverse in the function, but why is the distance (r) in the inverse squared? Is this the same principle of why s^-2 is the acceleration formula and time is square in the inverse?
Thanks.
[tex]\frac{(k)(e1)(e2)}{r^2}[/tex]
How does the inverse of r2 fit into the equation? I understand the concept of how distance would need to be the inverse in the function, but why is the distance (r) in the inverse squared? Is this the same principle of why s^-2 is the acceleration formula and time is square in the inverse?
Thanks.
Last edited: