Register to reply 
Force of attraction forumla 
Share this thread: 
#1
Nov2408, 05:09 PM

P: 19

The force of attraction formula between two charges is
[tex]\frac{(k)(e1)(e2)}{r^2}[/tex] How does the inverse of r^{2} fit into the equation? I understand the concept of how distance would need to be the inverse in the function, but why is the distance (r) in the inverse squared? Is this the same principle of why s^2 is the acceleration formula and time is square in the inverse? Thanks. 


#2
Nov2408, 06:01 PM

Mentor
P: 41,471

Coulomb's law is an example of an inverse square law, something quite common in physics. Read about it here: Inverse Square Law



#3
Nov2408, 07:06 PM

P: 19

I see! thanks!



#4
Nov2408, 09:33 PM

HW Helper
P: 7,131

Force of attraction forumla
Found the link for the other cases at the same site: electrical field For the infinite line case, the field strenth is a function of charge "density" over the perpendicular distance "z" to the line ( ... / z). For the infinite disc (plane) case, the limit as "R" approaches infinity, the [1  z/sqrt(z^2 + R^2) ] term approaches [1  0], and the field strength is constant, independent of distance 


#5
Nov2608, 03:11 AM

P: 6

Things get really cool when you start checking out far field proportionalities in systems of multipoles!



Register to reply 
Related Discussions  
Magnet's attraction/rejection Force  Introductory Physics Homework  13  
Attraction and gravitational force.  Advanced Physics Homework  5  
What Forumla?  Introductory Physics Homework  6  
Help... empirical forumla... : /  Chemistry  1 