
#1
Dec3108, 05:07 PM

P: 369

On the boundary (surface) of two regions, the tangential components of electric fields on above and below surface are continuous. I wonder if it is also true for displacement [tex]\vec{D}[/tex] and polarization [tex]\vec{P}[/tex]? That is, can I say:
the tangential component of [tex]\vec{D}[/tex] or [tex]\vec{P}[/tex] on above and below surface are continuous? For magnetic field, the statement of the magnetic field about [tex]\vec{B}[/tex] is: [tex](\vec{B}_{above}  \vec{B}_{below} )\cdot\hat{n} = 0[/tex] and [tex](\vec{B}_{above}  \vec{B}_{below} )\times \hat{n} = \mu_0\vec{K}[/tex] I wonder if [tex]\vec{K}[/tex] means the free current surface density? What is the boundary conditions for [tex]\vec{H}[/tex]? 



#2
Dec3108, 11:05 PM

P: 308

Do the two regions have the same dielectric constant? Think about the formula that relates D and E...




#3
Jan209, 06:47 PM

P: 369

By the way, in some text, it reads [tex](\vec{P}_2\vec{P}_1)\cdot\hat{n} = \sigma_p[/tex] and [tex]\sigma_p[/tex] is what we call the density of polarized charges. I wonder if this is the same name as bound charges which is used in other text? 



#4
Jan309, 12:40 PM

P: 308

boundary condition of EM field 


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