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How many Friday the 13ths would you expect in a year? 
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#1
Feb1309, 11:00 AM

P: 42

Today is Friday the 13th. It's the first of 3 this year. Is 3 more than you'd expect in a year?
Here's how I'd calculate it. 12 months, each with a 13th. 7 days in a week, so each month has 1/7 chance of having a Friday 13. 1/7 x 12 = 1.71. So this year is significantly more unlucky than others, I guess. OK, if I got this trivial math problem wrong, I'm really embarrassed, but so what. A more complex question would be whether or not numerically days of the week are evenly distributed, as I have assumed in my calculations. Also, does the occurrence of a Friday 13 effect the probability of another in the year? Interesting number theory questions with hints of chaos theory as well. 


#2
Feb1309, 11:28 AM

P: 266

Your calculation is spot on and in fact it's possible to determine the maximum number of Friday the 13ths as well as the minimum, but that involves accounting for months lengths and their remaining lengths divisibility 7, whatever days remain can be added successively to determine the amount of Friday the 13ths in any given year leap or otherwise. it is a tad more complicated, in fact I don't want to start working it out as I fear it'll eat up an hour or so and I already know the answer is 3 and 1.
I wouldn't be surprised though that once you had an answer you could work out the number of friday the 13ths from the first date they fell on accounting for leap years, and in fact I'm sure of it. 


#3
Feb1309, 11:33 AM

P: 344

By the way, JakeA, Chaos Theory despite its name is not even a theory. It is a branch of inquiry.



#4
Feb1309, 11:59 AM

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P: 15,173

How many Friday the 13ths would you expect in a year?
That said, there is nothing chaotic in this problem because there is no randomness in the problem. There is nothing random about whether April 13, 2525 falls on a Friday (it does). Determining the day of the week a particular date occurs on is a trick commonly learned by autistic savants. (I cheated and looked up a calendar for 2525.) 


#5
Feb1309, 02:26 PM

HW Helper
P: 2,264

In a 400 year cycle there are 688 F13's
So one expects E[F13]=688/400=1.72 F13/year So three is more than you expect in a year though maybe the 28 year cycle that covers all cases likely to arise in the lives of most now living should be used E[f13]=48/28=12/7~1.7143 in eith case we may note that about one year every 9 has 3 and the next one is 2015 


#6
Feb1309, 09:32 PM

P: 192

"In mathematics, chaos theory describes the behaviour of certain dynamical systems – that is, systems whose states evolve with time – that may exhibit dynamics that are highly sensitive to initial conditions (popularly referred to as the butterfly effect). As a result of this sensitivity, which manifests itself as an exponential growth of perturbations in the initial conditions, the behavior of chaotic systems appears to be random. This happens even though these systems are deterministic, meaning that their future dynamics are fully defined by their initial conditions, with no random elements involved. This behavior is known as deterministic chaos, or simply chaos." 


#7
Feb1309, 09:36 PM

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P: 12,071

At the risk of stating the obvious, if Friday the 13th falls in February of a non leapyear, then another must follow in March.
We got two for the price of one this year 


#8
Feb1309, 10:01 PM

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P: 15,173

There is a key word in that wikipedia article you quoted: "In mathematics, chaos theory describes the behaviour of certain dynamical systems ..." The calendar is not one of those dynamical systems. 


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