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SR Simultaneous Lines Drawn in the Sand |
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| Jun9-04, 02:15 AM | #35 |
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SR Simultaneous Lines Drawn in the Sandwhich is what i thought, so why the arguments if everyone agrees? |
| Jun9-04, 02:30 AM | #36 |
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Using the detected arrival times of the photons in the moving frame, SR theory calculates that the photons were not emitted simultaneouslly in the moving frame. THE PHOTONS WERE DETECTED SIMULTANEOUSLY IN THE MOVING FRAME AT THE INSTANT THE PHOTONS WERE EMITTED IN THE STATIONARY FRAME. All you theorists can argue all you want about SR theory, speed of light, Einstein, laws of physics, constancy of the speed of light foreever. The fact of the observation the photons were emitted simultaneously in the moving frame remains invariant under any theoretical perturbation. Your problem is one of embarrassment when you ponder: "How could I ever have accepted special relativity in the first place?" Like I said, it is your problem, you solve it. |
| Jun9-04, 02:40 AM | #37 |
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This is an experimental observation. And you say no they were not emmitted in the moving frame simultaneously. |
| Jun9-04, 02:43 AM | #38 |
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What are you talking about " ...seeming more intuitve . . ?.Aren't observations intuitive enough for you? |
| Jun9-04, 03:04 AM | #39 |
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why must you use a moving frame and a stationary frame?
i think that's what is throwing me off do one experiment where he's stationary and THEN do the exact same thing when it's moving combining the two creates unnecessary confusion :P 1) A -> ________________M________________ <- B 1) A ____ ->____________M____________<- ____ B 1) A __________ ->______M______<- __________ B 1) A _________________ xMx _________________ B 2) A -> ________________M________________ <- B 2) A ____ ->______________M__________<- ____ B 2) A __________ ->__________M__<- __________ B 2) A ________________ ->______Mx ___________ B 2) A ______________________ ->__Mx _________ B 2) A ____________________________xMx _______ B so i'm still not seeing the contradiction. everyone AGREES that the photons don't hit him at the same time in the moving frame. How hard would it be to do the calculations in reverse for the moving frame setup and acquire that the beams WERE emitted simultaneously BECAUSE of the frame shift, extrapolate it using M's velocity towards B. |
| Jun9-04, 05:14 AM | #40 |
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Because SR theory says that events that are simultaneous in the stationary frame are not simultaneous in the moving frame. We are talking about the same physical event. We must do the experiment with two frames, one stationary and one moving to test the theory. Hence we have the photo-sensitive strips to measuee the emission of the photons. Here is the contradiciton that everyone is having such a difficult time with. [b]"Were the photons that were emitted simultaneously in the stationary frame also emitted simultaneously in the moving frame?"[/b ] There was the record of the phosensitive strips attached to the moving frame that were exposed just when the photons were emitted in the stationary frame. These photo-sensitve strips were within a photon wave length of the emitted photons at A and B in the stationary frame when they wee exposed. SR theory says, the photons were not emitted simultaneously in the moving frame. SR Theory gets to work backwards in time and redo the physical events that occured there. |
| Jun9-04, 06:27 AM | #41 |
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Specifically, Geistkiesel is asserting that both of these diagrams are representing the exact same sequence of events: Code:
A M B A\ M /B A \ M / B A \ M / B A \ M / B A \ M / B A \M / B A M / B A M / B A M / B A M / B A M/ B A M B A\ M /B A \ M / B A \ M / B A \ M / B A \ M / B A \ M / B A \M/ B The first diagram depicts how things look in the rest frame of the lights, if the lights are activated simultaneously. The second diagram depicts how things look in the rest frame of the observer, if the lights are activated simultaneously. However, there is a very important difference between the two diagrams; in the first diagram the photons do not meet M at the same event, however in the second diagram the photons do meet M at the same event. The conclusion is that these diagrams cannot possibly represent the same events. Among the possible assumptions we can abandon, abanding that of absolute simultaneity is by far the most reasonable; the emission of photons is simply simultaneous in one frame but not the other. |
| Jun9-04, 07:59 AM | #42 |
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| Jun9-04, 08:07 AM | #43 |
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| Jun9-04, 08:17 AM | #44 |
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| Jun9-04, 08:18 AM | #45 |
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| Jun9-04, 08:36 AM | #46 |
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| Jun9-04, 08:57 AM | #47 |
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|||----M'----||| -->moving frame--> -A-----M-----B-| XX stationary frame XX This is the picture the instant photons were emitted from A and B in the stationary frame. Said another way, the instant the photo-sensitive strips were exposed in the moving frame by photons emitted in the stationary frame.. Is this enough "sense talk, man"? I title this: A Simultaneous Line in the Sand for Doc Al. If you were from Texas, or had spent any time in Texas, maybe, just maybe you would be able to understand. And this even though it is common knowledge that Texans have half their brains tied behind their back, leaving one loose piece of gray matter to rattle around inside their skull cavities. You defied anyone to understand the point. OK, someone from Texas, splain it to Doc Al. |
| Jun9-04, 09:07 AM | #48 |
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As from me to you, this is as nice as it gets. |
| Jun9-04, 10:40 AM | #49 |
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Depending on the theory you apply to the thought experiment, the outcome is different. Which is right and which is wrong? Well, that's a question answered by experimentation. What's funny about this is you think you're making an argument against Relativity, but what you are actually doing is demonstrating you don't even understand the scientific method, much less Relativity. The other guys here aren't so much defending Relativity as trying to explain to you what it says. |
| Jun9-04, 11:18 AM | #50 |
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Are the marks on the photo-sensitive strips (caused by the photon emissions) in the moving frame equally spaced from the point M' (which passed M at the exact moment that the clock at M read t=0): YES! Do the moving observers detect the photon emissions as happening simultaneously: NO! By building incorrect assumptions into your "thought" experiment, you have left the realm of real physics. (As we know it today.) Note that Einstein makes no such assumptions--and is able to simply deduce the relativity of simultaneity. Why not address Einstein's actual argument? |
| Jun9-04, 11:28 AM | #51 |
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(1) The marks on the photo-sensitive strips (caused by the photon emissions) in the moving frame are equally spaced from the point M' (which passed M at the exact moment that the clock at M read t=0): True! (2) That the moving observers detect the photon emissions as happening simultaneously: Not true! As long as you insist on adding these assumptions, there is no point in continuing the discussion. However, if you would like to discuss Einstein's actual argument--which you refer to constantly but obviously fail to grasp--have at it. If you truly understand Einstein's point, this should be no problem--since he makes fewer assumptions than you do. |
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