Annoying d/dx: A Quick Guide to Derivatives

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can you guyz help me with a quick derivative?

eeeex
 
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Hi LyleX^Y, Welcome to PF!:smile:

We're here to assist you, not to do your homework for you. As per forum rules, you must show some attempt at a solution, and are not supposed to ignore the homework help template.

So, what have you tried?
 
awww sorry this isn't a homework actually I am just thinking of a problem my teacher would do. hehe sorry

i got

d/dx=(eeeex)*(d/dx eeex)*(d/dx eex)*(d/dx ex)

i just can't get past that point i don't know how to do the product rule with 3 values.
 
LyleX^Y said:
awww sorry this isn't a homework actually I am just thinking of a problem my teacher would do. hehe sorry

i got

d/dx=(eeeex)*(d/dx eeex)*(d/dx eex)*(d/dx ex)

i just can't get past that point i don't know how to do the product rule with 3 values.

Well, so far so good:smile: (although it's the chain rule you're using, not the product rule)

Now try computing each of the derivatives in that product (use the chain rule again)... what are (d/dx eeex), (d/dx eex) and (d/dx ex)?
 
gabbagabbahey said:
Well, so far so good:smile: (although it's the chain rule you're using, not the product rule)

Now try computing each of the derivatives in that product (use the chain rule again)... what are (d/dx eeex), (d/dx eex) and (d/dx ex)?

dont i have to use the product rule for the 3 that i haven't take the d/dx of?

"(d/dx eeex), (d/dx eex) and (d/dx ex)?[/QUOTE]"
 
could we differentiate it like a^x by so it owuld be lna*a^x
 
LyleX^Y said:
dont i have to use the product rule for the 3 that i haven't take the d/dx of?

"(d/dx eeex), (d/dx eex) and (d/dx ex)?

No, since these aren't products -- they are function compositions, so you would need to use the chain rule. Think of it this way: if f(x) = ex, then eex = f(f(x)).
 
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LyleX^Y said:
awww sorry this isn't a homework actually I am just thinking of a problem my teacher would do. hehe sorry

i got

d/dx=(eeeex)*(d/dx eeex)*(d/dx eex)*(d/dx ex)

i just can't get past that point i don't know how to do the product rule with 3 values.

I forgot to put this in my previous post. It doesn't make any sense to start and equation with d/dx. It's very much like saying \sqrt = 3. Each of these symbols represents an operation that is yet to be performed.
 
cragar said:
could we differentiate it like a^x by so it owuld be lna*a^x

That's the wrong way to go, since it would make the problem more difficult for no purpose. The basic function in this problem is already "the" exponential function, ex.
 
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ok thanks... thanks for the help... got to go do my midterm hehe thanks again
 
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