Particle, kinetic energy, decay point

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SUMMARY

The discussion focuses on calculating the energy required for a particle with a rest mass energy of 150 MeV to ensure its decay point is distinguishable from its production point on a photographic plate, given a lifetime of 1.0 x 10^-16 s. The participant initially attempted to calculate the velocity using the formula v = distance/time, resulting in an impossible velocity exceeding the speed of light. The conversation highlights the need to consider the Lorentz transformations and the difference between the particle's rest frame and the lab's reference frame to solve the problem correctly.

PREREQUISITES
  • Understanding of special relativity concepts, including Lorentz transformations
  • Familiarity with the energy-mass equivalence principle (E=mc²)
  • Knowledge of kinetic energy calculations in relativistic physics
  • Basic grasp of the uncertainty principle in quantum mechanics (though not covered in this discussion)
NEXT STEPS
  • Study Lorentz transformations and their application in relativistic physics
  • Learn about the implications of time dilation and length contraction in different reference frames
  • Explore the relationship between kinetic energy and relativistic mass
  • Review the uncertainty principle and its relevance in particle physics
USEFUL FOR

Students of physics, particularly those studying special relativity and particle physics, as well as educators looking for problem-solving strategies in advanced mechanics.

Yroyathon
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Homework Statement


The lifetime of a particle is 1.0*10^-16 s in the particle's rest frame. With what energy would one of these particles have to be produced so that its decay point is distinguishable from its production point in a photographic plate? Assume that a 1 mm separation is required for a measurement. The particle mass corresponds to mc^2 = 150 MeV.

Homework Equations


energy of particle with no potential energy
E = gamma * m * c^2
where gamma = 1 / sqrt(1 - (v^2/c^2))

kinetic energy of a particle
K = m * c^2 * (gamma - 1)

The Attempt at a Solution


I tried calculating the velocity, v= 1*10^(-3)m / 1 * 10^(-16) s = 1 * 10^13 m/s. but this velocity is greater than c, which is both bad/impossible and prevents me from using other equations I have.

i feel like first I need to resolve this velocity problem before I can continue, since most of my energy equations in the textbook involve velocity, and this problem involving both a time and a distance lead me to believe velocity will be involved.

suggestions? hints?... anything would be appreciated.

Thanks.
,Yroyathon
 
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Use uncertainty principle.
 
well, Hm.

the uncertainty principle is in the next chapter, we haven't gone over it yet. So either there's been some sort of screwup and the prof or anyone hasn't noticed it, or there has to be a way to solve it without the uncertainty principle.
 
Remember, the lifetime given is that in the particle's rest frame. The lifetime seen in the lab's reference frame will be different.
 
aha. yes. that's definitely in this chapter, thanks. i'll dig back into the problem now and try to incorporate that info.
 
ok then. so I tried using the Lorentz transformations we have for t -> t', and x -> x', but I didn't now what to put for the u, the speed of the inertial frame. So I've got u's and gamma's floating around everywhere gumming up the works, keeping me from being able to solve explicitly for t and x', the time in the observation frame and the displacement in the particle's frame. Maybe this isn't the correct approach.

We've got some momentum and energy in special relativity material/equations, but my physic1&2 is pretty rusty, so setting up the problem is difficult. could someone explain at least part of the process or ideas involved?

I'm just flailing at the moment because I don't really know which approach to use now.
 

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