Particle, kinetic energy, decay point

AI Thread Summary
The discussion revolves around calculating the energy required for a particle with a lifetime of 1.0*10^-16 s to ensure its decay point is distinguishable from its production point by at least 1 mm. The participant initially calculated an impossible velocity exceeding the speed of light, indicating a misunderstanding of the relationship between time, distance, and velocity in relativistic contexts. They were advised to consider the effects of relativistic time dilation, as the lifetime in the lab frame differs from the particle's rest frame. The participant expressed confusion regarding the application of Lorentz transformations and the need for a clearer understanding of the relevant equations in special relativity. Overall, the conversation highlights the challenges of applying relativistic principles to solve the problem effectively.
Yroyathon
Messages
42
Reaction score
0

Homework Statement


The lifetime of a particle is 1.0*10^-16 s in the particle's rest frame. With what energy would one of these particles have to be produced so that its decay point is distinguishable from its production point in a photographic plate? Assume that a 1 mm separation is required for a measurement. The particle mass corresponds to mc^2 = 150 MeV.

Homework Equations


energy of particle with no potential energy
E = gamma * m * c^2
where gamma = 1 / sqrt(1 - (v^2/c^2))

kinetic energy of a particle
K = m * c^2 * (gamma - 1)

The Attempt at a Solution


I tried calculating the velocity, v= 1*10^(-3)m / 1 * 10^(-16) s = 1 * 10^13 m/s. but this velocity is greater than c, which is both bad/impossible and prevents me from using other equations I have.

i feel like first I need to resolve this velocity problem before I can continue, since most of my energy equations in the textbook involve velocity, and this problem involving both a time and a distance lead me to believe velocity will be involved.

suggestions? hints?... anything would be appreciated.

Thanks.
,Yroyathon
 
Physics news on Phys.org
Use uncertainty principle.
 
well, Hm.

the uncertainty principle is in the next chapter, we haven't gone over it yet. So either there's been some sort of screwup and the prof or anyone hasn't noticed it, or there has to be a way to solve it without the uncertainty principle.
 
Remember, the lifetime given is that in the particle's rest frame. The lifetime seen in the lab's reference frame will be different.
 
aha. yes. that's definitely in this chapter, thanks. i'll dig back into the problem now and try to incorporate that info.
 
ok then. so I tried using the Lorentz transformations we have for t -> t', and x -> x', but I didn't now what to put for the u, the speed of the inertial frame. So I've got u's and gamma's floating around everywhere gumming up the works, keeping me from being able to solve explicitly for t and x', the time in the observation frame and the displacement in the particle's frame. Maybe this isn't the correct approach.

We've got some momentum and energy in special relativity material/equations, but my physic1&2 is pretty rusty, so setting up the problem is difficult. could someone explain at least part of the process or ideas involved?

I'm just flailing at the moment because I don't really know which approach to use now.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top