
#1
Jun2204, 04:04 PM

P: 617

I have no idea how to do this problem or where to even start: Find the exponential function f(x) = Ca^x who’s graph is given. The graph has a concave up line, that intersects the yaxis at what looks like ½ (no exact intersection is given) and has the two points (1,6) and (3,24).




#2
Jun2204, 04:29 PM

P: 696

That the point (1, 6) lies on the graph means that f(1) = 6. But f(x) = Ca^x, so f(1) = Ca^1 = Ca = 6. You can find a similar equation using the other point. You now have two equations and two unknowns. Can you take it from there?




#3
Jun2304, 08:54 AM

Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 38,899

However, the graph of y= Ca^{x}, passing through (1,6) and (3,24) doesn't cross the yaxis anywhere near 1/2!




#4
Jun2304, 10:57 AM

Emeritus
Sci Advisor
PF Gold
P: 11,154

Exponential Funcitons 



#5
Jun2304, 04:01 PM

P: 617

That helps a lot, thank you. Sorry about the ½ thing, didn’t do a very good job of eyeballing it.



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