What is the exponential function with a concave up graph and two given points?

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    Exponential
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Discussion Overview

The discussion revolves around finding an exponential function of the form f(x) = Ca^x, given that its graph is concave up and intersects the y-axis at an approximate value, along with two specific points: (1, 6) and (3, 24).

Discussion Character

  • Homework-related, Mathematical reasoning, Conceptual clarification

Main Points Raised

  • One participant expresses uncertainty about how to approach the problem of finding the exponential function.
  • Another participant points out that since the point (1, 6) lies on the graph, it leads to the equation Ca = 6, which can be paired with a similar equation from the point (3, 24) to create a system of equations.
  • There is a challenge regarding the y-intercept, with one participant asserting that the graph does not intersect the y-axis at 1/2, but rather at 3/2.
  • A later reply acknowledges the correction regarding the y-intercept and expresses gratitude for the clarification.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the exact y-intercept of the graph, with differing views on its value. The discussion remains unresolved regarding the complete solution to finding the exponential function.

Contextual Notes

The discussion includes assumptions about the graph's shape and the accuracy of the y-intercept estimation, which may affect the interpretation of the problem.

JonF
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I have no idea how to do this problem or where to even start: Find the exponential function f(x) = Ca^x who’s graph is given. The graph has a concave up line, that intersects the y-axis at what looks like ½ (no exact intersection is given) and has the two points (1,6) and (3,24).
 
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That the point (1, 6) lies on the graph means that f(1) = 6. But f(x) = Ca^x, so f(1) = Ca^1 = Ca = 6. You can find a similar equation using the other point. You now have two equations and two unknowns. Can you take it from there?
 
However, the graph of y= Cax, passing through (1,6) and (3,24) doesn't cross the y-axis anywhere near 1/2!
 
HallsofIvy said:
However, the graph of y= Cax, passing through (1,6) and (3,24) doesn't cross the y-axis anywhere near 1/2!

It crosses at y=3/2.
 
That helps a lot, thank you. Sorry about the ½ thing, didn’t do a very good job of eyeballing it.
 

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