Why does the following function equate to a delta in classical feild theory

Fwahnak
Messages
5
Reaction score
0

Homework Statement



Can anyone remember a decent argument/derivation for the following representation of the delta function.


Homework Equations



$ \nabla^2 \frac{1}{|r|} =\delta(r)$

(probally up to some multipicative constant $\frac{1}{2\pi}$ or something

The Attempt at a Solution



I know I've seen an agrument in jackson but I don't have a copy.
 
Last edited:
Physics news on Phys.org
I've no confidence that I've latexed that correctly and my work computer won't show me the symbols so here's the equation in equation again

div(grad(1/|r|)) is proportional to deltafunction(r)
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top