Ideal Projectile Motion , horizontal and vertical components

AI Thread Summary
To solve the projectile motion problem, the horizontal and vertical components of the ball's velocity must be calculated. The horizontal component (Vx) is correctly determined as 24.513 m/s using Vx = 32 m/s * cos(40°). The vertical component (Vy) is initially calculated as 20.569 m/s, but the method for finding the height at which the ball hits the wall needs clarification. The time to reach the wall is calculated using t = distance / Vx, and the vertical position can be found with y = Vy*t - 1/2*g*t^2. This approach will yield the height above the release point where the ball strikes the wall.
djester555
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Homework Statement



You throw a ball toward a wall with a speed of 32 m/s at an angle of 40.0° above the horizontal directly toward a wall (Fig. 5-33). The wall is 22.0 m from the release point of the ball.


(a) How far above the release point does the ball hit the wall?
not sure what to do

(b) What are the horizontal and vertical components of its velocity as it hits the wall?

Vx = 32m/s * cos 40
Vx 24.513 i know this is correct
Vy = 32m/s * Sin 40
Vy= 20.569 this isn't correct i don't know what i did wrong
 
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Distance of the wall is given. The time taken by ball to reach the wall is
t = d/vx.
Using
y = vy*t - 1/2*g*t^2, find y, and vy at that point
 
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