energy, nonconservative and conservative forces questionby holezch Tags: conservative, energy, forces, nonconservative 

#1
Dec3109, 07:30 PM

P: 253

1. The problem statement, all variables and given/known data
An object with an initial velocity V0 of 14 m/2 falls from a height of 240m and buries itself in 0.20 m of sand. The mass of the body is 1.0 kg. Find the average resistive force exerted by the sand on the body. Neglect air resistance. 2. Relevant equations change in K = W (of resultant force) change in K + change in U (potential energy) = 0 [conservative forces] change in K + change in U + work done by friction = 0 [non conservative friction]\ ...et c 3. The attempt at a solution Solution from textbook: the kinetic energy of the body as it is about to hit the sand: K = (mV0^2)/2 + mgh where m is mass g is gravity h is the height from the sky to the sand Also, from the workenergy principle: (then it says "approximately") K = Fs, where F is the average resistive force of the sand onto the body and s is the distance into the sand. This part is weird to me.. shouldn't change in K equal to the work done as the object falls from the sky? How come K = Fs? Then they just plug things in and solve.. I just don't get how they could just ignore the nonconservative force from friction and how they could just say that K = Fs.. Thank you.. please help 



#2
Dec3109, 08:24 PM

Sci Advisor
HW Helper
PF Gold
P: 5,961

It's a bit confusing the way the problem was solved. They first considered the KE of the object just before it hit the ground, using conservation of Mechanical Energy with only conservative forces acting (there is no friction during the fall, neglecting air resistance). That's your second equation. Then the second part uses the work enrgy theorem, and neglects the work done by gravity in that short distance through the sand (W_c +W_nc = delta KE, where W_c is neglected). The more exact solution utilizes your 3rd equation, from start point to end point.




#3
Dec3109, 09:03 PM

P: 253

Hi, thank you so much for replying. I think I'm still confused: W = Fs = change in K, K1  K0.. We have K0 as it's about to go into the ground, K0 = (mV0^2)/2 + mgh. K1, we don't know, but it should be something like W (by conservative forces) + W (by friction) + K0. But then... K0 = Fs. Also, how can they just omit things? Maybe it's due to the fact that it's the average? I can't quite what the difference between finding the average and finding the precise force would be.. Is it just average because we're assuming that the sand resistance is always the same? Thank you, this is as much as I understand right now :S thank you for your patience. EDIT: Okay, so they some how neglected the gravity, and they got K1  K0 = work by friction = Fs. Still, that would be K1  K0, and not K0 = Fs? [I posted the question above denoting K0 as K] 



#4
Dec3109, 09:14 PM

Sci Advisor
HW Helper
PF Gold
P: 5,961

energy, nonconservative and conservative forces question 



#5
Dec3109, 09:22 PM

P: 253

Then 0  K0 = ((mV0^2)/2 + mgh) = Fs? The book says (mV0^2)/2 + mgh) = Fs.. Okay, I understand everything else :) Thanks so much! 



#6
Dec3109, 09:48 PM

Sci Advisor
HW Helper
PF Gold
P: 5,961





#7
Dec3109, 09:51 PM

P: 253

Thank you so much :) and I especially appreciate you helping me during new year's eve :) Happy new year! 



#8
Dec3109, 09:56 PM

Sci Advisor
HW Helper
PF Gold
P: 5,961

Edit: And what a disappointment it was, they didn't even show the ball at midnight, its all computerized at a cost of millions, and I don't think the thing even drops anymore...Bring back the old days when the ball cost 10 bucks and did something, and American Bandstand and Dick Clark were in their prime..... 


Register to reply 
Related Discussions  
Energy and conservative forces  Introductory Physics Homework  12  
Conservative and nonconservative forcesproblems  Introductory Physics Homework  16  
Potential Energy & Conservative Forces #18  Introductory Physics Homework  9  
Potential Energy & Conservative Forces #20  Introductory Physics Homework  13 