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#91
Feb2811, 08:35 AM

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P: 6,041

Ok let's crank it out. P1 is (20)(2.15) = 43 and P2 is (20/2)(2.15) = 21.5, so the vert load is 64.5 N. The moment about the support is 43[(2.15/2) +.1 + 4 sin15] + 21.5[(2.15/3) + .1 + 4 sin15] = 134.9 Nm. Or, if you look at the moment at the support in the free body of the slanted member, it's 64.5(4)(sin15) + 68.1 = 134.9 Nm.....checks out OK.



#92
Feb2811, 09:58 AM

P: 70

Using the bending equations, I have a value of approx 88Pa for the induced stresses.
Am I right in using the the biggest moment in the equation, which is at the ground? 


#93
Feb2811, 10:42 AM

P: 70

Sorry, 44.24MPa



#94
Feb2811, 11:27 AM

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#95
Mar111, 07:33 AM

P: 3

Hi, i am having the same trouble with this assignment, mainly drawing the free body diagram of each section. Not sure exactly whether to draw it as a full frame or two seperate parts.
thanks 


#96
Mar111, 09:30 AM

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#97
Mar111, 09:49 AM

P: 3

Thanks, so for the horizontal piece, when your working out the vertical forces, how do you know whether to use the 20Mn or the 40Mn? and does it only have 2 downward forces due to the billboard and one moment force due to the slanted piece?
Thank you 


#98
Mar111, 09:51 AM

P: 3

sorry i ment 20Nm and 40Nm



#99
Mar111, 12:24 PM

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