Can Fe2+ Reduce Sn2+ to Sn Metal?

In summary, the question is whether Fe2+(aq) can reduce Sn2+(aq) to Sn metal. The standard reduction potentials for these ions are -0.14 and -0.44, respectively. Since Sn has a more positive Epot, it has a greater tendency to be reduced. After adding the two potentials, we get a positive value, indicating that this reaction can occur. However, this is incorrect because Fe2+ must be oxidized to Fe3+ in order to act as a reducing agent. The correct balanced reaction equation should be written to show this.
  • #1
kooombaya
36
0
Is Fe2+(aq) capable of reducing Sn2+(aq) to Sn metal?



The standard reduction potentials from my book are -0.14 for Sn2+ and -0.44 for Fe2+



Because Sn has a more positive Epot it has a greater tendency to be reduced. So add the Epot up: -0.14 + 0.44 (oxidation)= 0.3. It's positive so this reaction can occur. However my answer key says the opposite. Can someone explain please? Thanks.
 
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  • #2
You are looking at the wrong potential for iron. -0.44 means iron gets reduced to metallic Fe, you want it to be a reducing agent - that means it has to be oxidized to Fe3+.

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  • #3
Borek wrote: You are looking at the wrong potential for iron. -0.44 means iron gets reduced to metallic Fe, you want it to be a reducing agent - that means it has to be oxidized to Fe3+.

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Yes I know. Here's the way I have it set up:
Fe --> Fe2+ + 2e Eox = 0.44V
Sn2+ + 2e --> Sn Ered = -0.14V

Adding the half reactions I get Ecell = 0.44-0.14 = 0.3 which is positive so the reaction goes. Apparently this is wrong though. I'm confused...
 
  • #4
You know you are wrong, yet you repeat the same mistake? You have selected wrong reaction for iron. If you have a solution containing Fe2+ and Sn2+ you can't get both reduced to metal at the same time. If one gets reduced, the other has to be oxidized.

Try to write balanced reaction equation. Remember Fe2+ and Sn2+ are your rectants.

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methods
 
  • #5
Oh I see! Thanks so much Borek!
 

1. How does Fe2+ reduce Sn2+ to Sn metal?

The reduction of Sn2+ to Sn metal by Fe2+ involves a redox reaction, where Fe2+ acts as the reducing agent and Sn2+ acts as the oxidizing agent. The Fe2+ ions donate electrons to the Sn2+ ions, causing them to gain electrons and form Sn metal.

2. What are the conditions required for Fe2+ to reduce Sn2+ to Sn metal?

The reduction reaction between Fe2+ and Sn2+ requires an acidic environment and the presence of a catalyst, such as H+ ions or a suitable enzyme. The reaction also typically occurs at high temperatures and in the absence of oxygen.

3. Can other metals be reduced by Fe2+ in a similar manner?

Yes, Fe2+ can reduce many metals, including Cu2+, Ag+, and Au3+. However, the effectiveness of Fe2+ as a reducing agent depends on various factors, such as the standard electrode potential and the availability of other reducing agents in the system.

4. What is the purpose of reducing Sn2+ to Sn metal?

The reduction of Sn2+ to Sn metal is used in various industrial processes, such as the production of tin cans and tin-coated steel. It is also an important step in the extraction of tin from ores, where Sn2+ ions are reduced to Sn metal using a more reactive metal like Fe2+.

5. Is the reduction of Sn2+ to Sn metal reversible?

Yes, the reduction of Sn2+ to Sn metal is reversible under certain conditions. If the concentration of Sn2+ ions is increased or the concentration of Fe2+ ions is decreased, the reverse reaction can occur, where Sn metal is oxidized back to Sn2+ ions. This equilibrium can be shifted by changing the reaction conditions, such as the pH or temperature.

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