Differentiating Hyperbolic Functions

BoT
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1. Differentiate cosh(x) using first principles



2. cosh(x) = (e^x+e^-x)/2


From previous exercises, I know the answer will be sinh(x)= (e^x-e^-x)/2 but I cannot get to the answer.
I seem to be left with the equation: lim h ---> 0 (e^2x*e^2h +1-e^h*2e^x +e^h)/(2h*e^x*e^h)
But when you make h=0 , it becomes underfined?

Homework Statement

 
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Where did you get e2x and whatnot from?

Just simplify

\frac{e^{x+h}+e^{-(x+h)}-(e^x+e^{-x})}{2h}


and then factorize.
 
I got it to

ex*eh+e-x*e-h -ex -e-x/ 2h

But how do I simplify this?
This is the part that always screws me up!
 
BoT said:
I got it to

ex*eh+e-x*e-h -ex -e-x/ 2h

But how do I simplify this?
This is the part that always screws me up!

Factor out ex from ex*eh and ex. Do a similar exercise with e-x from the terms.

Then compute the limits.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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