|Apr22-10, 11:06 AM||#1|
stored spring energy
Hi - Would someone check my method here please?
1. The problem statement, all variables and given/known data
Two trolleys A and B, of mass 0.70kg and 0.80kg respectively, are on a horizontal track and held together by a compressed spring. When the spring is released the trolleys separate freely and A moves to the left with an initial velocity of 4.0m/s.
a) the initial velocity of A
b) the energy initially stored in the spring
2. Relevant equations
3. The attempt at a solution
b) This is a transfer of elastic potential energy to kinetic energy -
1/2(0.70x4.0)^2 + 1/2(0.80x3.5)^2
=0.0392 + 3.92
|Apr22-10, 11:34 AM||#2|
KE = 1/2mv^2, but you calculated 1/2(mv)^2. Not the same!
|Apr22-10, 11:40 AM||#3|
ahh of course:
(1/2x0.7x4.0^2) + (1/2x0.8x3.5^2) = 10.5 J
|Apr22-10, 12:44 PM||#5|
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