Quick Calc 1 problem (Antiderivative)

btbam91
Messages
91
Reaction score
0
Hello, I'm looking for f given f'' and two conditions.

[PLAIN]http://img375.imageshack.us/img375/2572/antider.jpg

Going from f'' to f', I get f'(x) = 5x^4 + 4x^3 + 4x + C

But with the two conditions, I feel that I cannot progress from here. I feel that one of those conditions should be f'.


Any help is appreciated. Thanks.
 
Last edited by a moderator:
Physics news on Phys.org
btbam91 said:
Hello, I'm looking for f given f'' and two conditions.

[PLAIN]http://img375.imageshack.us/img375/2572/antider.jpg

Going from f'' to f', I get f'(x) = 5x^4 + 4x^3 + 4x + C

But with the two conditions, I feel that I cannot progress from here. I feel that one of those conditions should be f'.


Any help is appreciated. Thanks.
Antidifferentiate one more time to get f(x). You'll get another constant of integration, say D. Using f(0) = 2 and f(1) = 1, you'll have two equations in two unknowns, so you should be able to solve for C and D.
 
Last edited by a moderator:
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top