Integral Question: Deriving Formula for $\int|f(x)|dx$

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The discussion centers on deriving the integral of the absolute value of a continuous function, specifically $\int |f(x)|dx$, where f(x) is a real-valued function. Participants note that the integral can be approached by considering the sign of f(x) and suggest breaking it into piecewise segments based on the function's behavior. It is emphasized that |f(x)| equals f(x) when f(x) is non-negative and -f(x) when f(x) is negative. The conversation includes some light-hearted banter about clarity in notation and the importance of precise definitions. Ultimately, the focus remains on finding a method to compute the area under the curve of |f(x)|.
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Hello everyone! Can anyone tell me a formula (or a way to derive) this integral?
\int|f(x)|dx
where f(x) is a real, continuous function of x in the vector space C^\infty. So far, all I've figured out is that odd-order integrations are related to the signum function.
Thanks!
 
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Derive or find the area under |f(x)|?

|f(x)| = f(x), if x >=0; -f(x), if x<0

so &Int; |f(x)| dx has 2 solutions: F(x), and -F(X), where F(X) is the antiderivative of f(x).
 
PrudensOptimus said:
Derive or find the area under |f(x)|?

|f(x)| = f(x), if x >=0; -f(x), if x<0

so &Int; |f(x)| dx has 2 solutions: F(x), and -F(X), where F(X) is the antiderivative of f(x).

No, |f(x)| = f(x) if f(x) >= 0 and -f(x) if f(x) < 0.

I recommend breaking up the integral into separate domains as I've indicated and integrating piecewise.
 
Tide said:
No, |f(x)| = f(x) if f(x) >= 0 and -f(x) if f(x) < 0.

I recommend breaking up the integral into separate domains as I've indicated and integrating piecewise.
Stop repeating my answers :p
 
PrudensOptimus said:
Stop repeating my answers :p

LoL! Man, I've just GOTTA get some reading glasses! :bugeye:
 
He wasn't repeating your answers. Prudens used x, while Tide correctly used f(x).
 
what i really meant was f(x)... but i was thinking about beer.
 
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