- #1
geminigirl15
- 4
- 0
Homework Statement
A mixture of phosphoric acid and NaH2PO4 are titrated against 0.151 M NaOH. The first equivalence point is at 0.00345 L and the second equiv point is at 0.01288 M.
The volume of the total mixture was 60 ml.
Calculate the concentration of both the phosphoric acid mixtures (H3PO4 and NaH2PO4)
Homework Equations
H3PO4 + NaOH => NaH2PO4 + H2O
The Attempt at a Solution
Iv made the titration graphs and figured out the endpoints (mentioned above).
Here's an attempt at the solution...
moles H3PO4 = Conc of NaOH x volume of NaOH at 1st eq.point.
= 0.151 x 0.00345 = 0.000521 mol
moles H2PO4 = conc of NaOH x vol of NaOH at 2nd eq. point
= 0.00143 mol
Im still unsure and pretty confused... Any help please? Thanks!