Electromagnetism - Find length of coil

AI Thread Summary
To calculate the length of an iron-free cylindrical coil with 9400 turns and an inductance of 68 mH, the formula L = N²μ₀μᵣA/l is used, where μ₀ is the magnetic field constant. The challenge arises from the unknown relative permeability (μᵣ) and cross-sectional area (A) of the coil. The thickness of the wire is given as 0.6 cm, which helps in determining the cross-sectional area for calculations. The discussion emphasizes the importance of unit consistency, noting that length should be in meters, area in square meters, and inductance in Henrys. Ultimately, the problem requires careful consideration of material properties and geometry to solve for the coil length.
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Homework Statement


Calculate the length l of an an iron-free cylindrical coil if it has 9400 turns (N), a thickness of 0.6cm and an inductance L = 68 mH. Take magnetic field constant \muo = 4\pi x 10-7 Wb/Am

(a) l = 63mm
(b) l = 54mm
(c) l = 46mm
(d) l = 36mm

Homework Equations



L = N2 \muo \mur A / l

The Attempt at a Solution



0.068 = (9400)2 x ( 4\pi x 10-7) \mur A / l

how to calculate if \mur and A are not given??
 
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Given that the core is iron-free, what sort of material would you expect to find there? This material has a very nice relative permeability for calculations!

If you have a (circular cross section of a) piece of wire that is 0.6cm thick (diameter), what is the (cross sectional) Area of this wire?

*NB: Beware of units, as 'l' is in meters, 'A' is in meters squared and 'L' is in Henry's.
 
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