# Rubber bands and Hooke's Law

by Manchot
Tags: bands, hooke, rubber
 P: 728 I have found a website which claims that rubber bands obey a force law $$F=-kT(x-\frac{1}{x^2})$$ $$x=\frac{L}{L_0}$$ While this is similar to Hooke's Law in the sense that it *almost* approaches it for large values of x, it is also quite different. Can anyone confirm or deny the formula's reliability? Thanks.
 Emeritus Sci Advisor PF Gold P: 11,155 Are you sure $x = L/L_0~~and~not~~\delta L/L_0~$ ?
 P: 728 No, I'm not sure.
 HW Helper P: 2,279 Rubber bands and Hooke's Law Well if you're familiar with elasticity you can formulate Hooke's Law in its terms, Stress = Modulus of Elasticity x Relative Deformation For a longitudinal deformation, the modulus is called Young's modulus $$\sigma = Y \delta L$$ Since Stress = Force/Area $$\frac{F}{A} = Y \delta L$$ $$F = YA \delta L$$ You know $$\delta L = \frac{\Delta L}{L_{o}}$$ $$F = YA \frac{\Delta L}{L_{o}}$$ Rearranging $$F = \frac{YA}{L_{o}} \Delta L$$ we have $$F = \frac{YA}{L_{o}} \Delta L$$ Hooke's Law $$F = k \Delta x$$ where k in our equation is (x = L) $$k = \frac{YA}{L_{o}}$$ The people from that page probably tried something similar, can you give us the website?
 Sci Advisor HW Helper PF Gold P: 12,016 The given formula, in order to be meaningful must have $$x=\frac{L}{L_{0}}$$ Rewritten slightly, it simply says: $$F=-kT\delta{L}({1+\frac{1}{x}+\frac{1}{x^{2}}})$$ Hence, it predicts a hardening for compression of the rubber. I don't know if it actually is good, though..
 P: 728 This is the website that I got the information from: http://www.newton.dep.anl.gov/askasc...0/phy00525.htm . It's about two-thirds down the page.