# Show the hex representation of MIPS instructions

by shieldcy
Tags: instructions, mips, representation
 P: 5 Hey all 1. The problem statement, all variables and given/known data Here i want to translate them and show the hex representation of these instructions: 1)add $t0,$t0, $zero 2)lw$t2, 16($s3) 2. Relevant equations 3. The attempt at a solution eg. 2) lw |$s3 | \$t2 | 16 I-TYPE then translate the assembly code: 35 | 19 | 10 | 16 The solution is 0x8E6A0010 But i 've no idea how the answer has been reached... Any help? Thank's a lot
 P: 90 What is the context of this question? Should you be able to answer it on a test or is it a homework problem meant to familiarize you with your assembler? I would write the code, compile it, and view the answer by stepping through the code.
 P: 5 It's an exam type question but MIPS assembly language table (http://en.wikipedia.org/wiki/MIPS_ar...embly_language) will be provided in exams
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P: 1,021

## Show the hex representation of MIPS instructions

Looks like you have decomposed the assembly instruction correctly:

3510 = instruction
1910 = s
1010 = t
1610 = C

Convert the base-10 values that you obtained into binary. Then group your binary results into the following I-type format:
[iiiiiiss] [sssttttt] [CCCCCCCC] [CCCCCCCC]

(use 6-bits of your instruction result, 5-bits of s, 5 of t, 16 bits of C, zero-padding as needed)

Then convert each 8-bit group to its hexadecimal equivalent.
 P: 5 thank you so much! cheers ;)
 P: 5 Could you please show me the way to convert hex value 0x8E6A0010 to decimal?
P: 90
 Quote by shieldcy Could you please show me the way to convert hex value 0x8E6A0010 to decimal?
The nth digit corresponds to how many b^n's there are, starting at n = 0, where b is the base (16 here).

0*16^0 + 1*16^1 + 0*16^2 + ... + 8*16^7
 P: 5 Oo yeah... thank's man ;)
P: 90
 Quote by shieldcy Oo yeah... thank's man ;)
No problem. That method works for converting any integer of any base into base 10 (you can even convert base 10 into base 10 with it).

e.g.
10110 base 2 = 0*2^0 + 1*2^1 + 1*2^2 + 0*2^3 + 1*2^4 = 2 + 4 + 16 = 22

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