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Show the hex representation of MIPS instructions

by shieldcy
Tags: instructions, mips, representation
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May22-11, 06:03 PM
P: 5
Hey all
1. The problem statement, all variables and given/known data
Here i want to translate them and show the hex representation of these instructions:
1)add $t0, $t0, $zero
2)lw $t2, 16($s3)

2. Relevant equations
3. The attempt at a solution
eg. 2)
lw | $s3 | $t2 | 16

then translate the assembly code:
35 | 19 | 10 | 16

The solution is 0x8E6A0010
But i 've no idea how the answer has been reached... Any help?
Thank's a lot
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May22-11, 06:27 PM
P: 90
What is the context of this question? Should you be able to answer it on a test or is it a homework problem meant to familiarize you with your assembler? I would write the code, compile it, and view the answer by stepping through the code.
May22-11, 06:46 PM
P: 5
It's an exam type question but MIPS assembly language table ( will be provided in exams

May23-11, 03:00 AM
PF Gold
P: 1,053
Show the hex representation of MIPS instructions

Looks like you have decomposed the assembly instruction correctly:

3510 = instruction
1910 = s
1010 = t
1610 = C

Convert the base-10 values that you obtained into binary. Then group your binary results into the following I-type format:
[iiiiiiss] [sssttttt] [CCCCCCCC] [CCCCCCCC]

(use 6-bits of your instruction result, 5-bits of s, 5 of t, 16 bits of C, zero-padding as needed)

Then convert each 8-bit group to its hexadecimal equivalent.
May23-11, 10:10 AM
P: 5
thank you so much! cheers ;)
May23-11, 11:13 AM
P: 5
Could you please show me the way to convert hex value 0x8E6A0010 to decimal?
May23-11, 11:48 AM
P: 90
Quote Quote by shieldcy View Post
Could you please show me the way to convert hex value 0x8E6A0010 to decimal?
The nth digit corresponds to how many b^n's there are, starting at n = 0, where b is the base (16 here).

0*16^0 + 1*16^1 + 0*16^2 + ... + 8*16^7
May23-11, 11:54 AM
P: 5
Oo yeah... thank's man ;)
May23-11, 12:24 PM
P: 90
Quote Quote by shieldcy View Post
Oo yeah... thank's man ;)
No problem. That method works for converting any integer of any base into base 10 (you can even convert base 10 into base 10 with it).

10110 base 2 = 0*2^0 + 1*2^1 + 1*2^2 + 0*2^3 + 1*2^4 = 2 + 4 + 16 = 22

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