Power transferred to resistance

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AI Thread Summary
The discussion focuses on calculating the average power transferred to a speaker with a resistance of 10.4 Ohms, in a circuit that also includes an additional resistance of 8.20 Ohms. The presence of the extra resistance affects the current flowing through the circuit, acting as a voltage divider that reduces the voltage across the speaker. To find the average power, the RMS values for voltage and current must be used, derived from the maximum voltage of the AC source. Participants emphasize the importance of understanding how series resistances interact in the circuit. The key takeaway is that the additional resistance significantly impacts the power calculation for the speaker.
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Homework Statement


Speaker Resistance = 10.4 Ohm
R = 8.20 Ohm
Maximum voltage of AC source = 15.0 V

What's the average power transferred to the speaker?

Homework Equations



P = I^2R
Imax = I/2^0.5

The Attempt at a Solution



I could the problem if there was only the speaker resistance. I don't understand how the other resistance comes into play or what it does in the circuit.
 
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Hi Tosh5457! :smile:
Tosh5457 said:
I could the problem if there was only the speaker resistance. I don't understand how the other resistance comes into play or what it does in the circuit.

The extra resistance reduces the current, I. :wink:
 
The other resistance, in series with the speaker resistance, form a voltage divider. Only a fraction of the supply voltage will appear across the speaker resistance.

You can determine the current through the series connected resistors, then using that current find the voltage developed across the speaker.

Keep in mind that you've been given the maximum voltage of the AC source. To find the average power you'll want the RMS values for voltage and current delivered to the speaker.
 
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