Understanding Aging and Time Dilation: The Twin Paradox Explained

jbar18
Messages
53
Reaction score
0
After a fairly long time of thinking I had a decent grip on the concept of time dilation, it has suddenly occurred to me that I don't. My issue is with the concept of the aging twins thought experiment (or whatever it's called) where if one shoots off at some comparable speed to the speed of light they will come back and be relatively younger than the twin that didn't move.

I will quote from wikipedia: "Time dilation would make it possible for passengers in a fast-moving vehicle to travel further into the future while aging very little, in that their great speed slows down the rate of passage of on-board time."

My issue with this is that relative to each twin, they themselves do not move at all. I.e. Each will observe the other to move slower through time than themselves. So then, if one twin shoots off at, say, 0.9c, there will be significant time dilation, and they will observe their twin staying young while they themselves age. My question is, how is it possible for both twins to witness each other age slower than themselves? In other words, who would be older when the twin came back?

I've read through many threads like this in the past and nodded my head thinking I understood, but now it seems apparent that I don't.
 
Physics news on Phys.org
After a quick bit of research, I have found an analogous problem for length contraction called the "ladder paradox" thought experiment. I suppose this is kind of the same as that, but for time dilation. I still don't get it though. Can someone explain it so that this simpleton can understand??
 
jbar18, Maybe I can save you some time from reading that other thread. I think it takes them a while to get to the point. Your question is exactly why Einstein was asked. And if I recall correctly, it took him a couple months to answer. To me, the importance of this question doesn't happen until the twins get back together. In that case, the traveling twin has to turn around. That's what makes them different. If you try keeping tract of simultaneity from the traveling twin's point of view, then simultaneity jumps forward quite a bit along the Earth bound twin's timeline. So in a way, you could say that the Earth bound twin does a lot of aging during the traveler's turnaround. Does that help?
 
OK, so this has bugged me for a while about the equivalence principle and the black hole information paradox. If black holes "evaporate" via Hawking radiation, then they cannot exist forever. So, from my external perspective, watching the person fall in, they slow down, freeze, and redshift to "nothing," but never cross the event horizon. Does the equivalence principle say my perspective is valid? If it does, is it possible that that person really never crossed the event horizon? The...
From $$0 = \delta(g^{\alpha\mu}g_{\mu\nu}) = g^{\alpha\mu} \delta g_{\mu\nu} + g_{\mu\nu} \delta g^{\alpha\mu}$$ we have $$g^{\alpha\mu} \delta g_{\mu\nu} = -g_{\mu\nu} \delta g^{\alpha\mu} \,\, . $$ Multiply both sides by ##g_{\alpha\beta}## to get $$\delta g_{\beta\nu} = -g_{\alpha\beta} g_{\mu\nu} \delta g^{\alpha\mu} \qquad(*)$$ (This is Dirac's eq. (26.9) in "GTR".) On the other hand, the variation ##\delta g^{\alpha\mu} = \bar{g}^{\alpha\mu} - g^{\alpha\mu}## should be a tensor...
ASSUMPTIONS 1. Two identical clocks A and B in the same inertial frame are stationary relative to each other a fixed distance L apart. Time passes at the same rate for both. 2. Both clocks are able to send/receive light signals and to write/read the send/receive times into signals. 3. The speed of light is anisotropic. METHOD 1. At time t[A1] and time t[B1], clock A sends a light signal to clock B. The clock B time is unknown to A. 2. Clock B receives the signal from A at time t[B2] and...

Similar threads

Replies
23
Views
3K
Replies
71
Views
5K
Replies
21
Views
2K
Replies
54
Views
3K
Replies
10
Views
2K
Replies
4
Views
1K
Replies
16
Views
2K
Back
Top