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Convergance and Divergence.. Could someone go over a routine to help determine them? |
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| Oct14-11, 11:05 AM | #1 |
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Convergance and Divergence.. Could someone go over a routine to help determine them?
Hey there..
Basically I'm struggling with convergence and divergence of series. I can see if converges and diverges by common sense and thinking through in my head but I struggle to write it down. The definitions in books seem confusing. Are there any steps I can systematically do every time which will help me determine on paper if the said series div. or conv.? For example a basic typical question in my course is like the following: as n ---> infinity [itex]\sum[/itex] (n^2 - 1) / (n^4 + 1) Some detailed exlanation in basic language would be greatly appreciated Regards Tam |
| Oct14-11, 11:55 AM | #2 |
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There are many different tools to test the convergence of a series, the most common probably being the comparison test, the integral test, the ratio test, and the nth root test. Here's a link with a big list: http://www.math.hmc.edu/calculus/tutorials/convergence/
In your particular example, I think comparison with the series [itex] \sum_{n=1}^\infty \frac{1}{n^2}[/itex] is the easiest test to use. |
| Oct15-11, 12:43 AM | #3 |
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Here are some urls with good information on this topic
http://online.math.uh.edu/HoustonACT/ http://online.math.uh.edu/HoustonACT...lus/index.html http://www.khanacademy.org/#calculus http://www.stewartcalculus.com/media...t=2&show_cat=2 |
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