# 1 = v^2 + t^2? and look at spacetime as velocity as x axis, time as y axis.

by darkhorror
Tags: axis, spacetime, time, velocity
 P: 137 I am not so sure how to explain this. But when looking at sqrt( 1 - v^2/c^2 ) for time dilation. It seems to follow that you may be able to think about it as 1 = v^2 + t^2 if look at v as fraction of c, and t as the amount a clock will be dilated. Then you could think about it in your frame of reference that all objects are moving at 1 through spacetime. If the velocity of an object gets larger then that just means that the t gets smaller.
 PF Patron P: 4,163 You explained it very well. The equation you derived is for the reciprocal of gamma, the time dilation factor. It plots as a circle. See this post: http://physicsforums.com/showpost.ph...81&postcount=6
 P: 4 I think it's more like sqrt(x^2 + y^2 + z^2 + t^2) = 1 4 dimensional law of pythagoras, using space and time. next step is using this to understand / work out a twin paradox :)
P: 2,180

## 1 = v^2 + t^2? and look at spacetime as velocity as x axis, time as y axis.

that should be a - t^2 right?
PF Patron
P: 260
 Quote by HotBuffet I think it's more like sqrt(x^2 + y^2 + z^2 + t^2) = 1 4 dimensional law of pythagoras, using space and time. next step is using this to understand / work out a twin paradox :)
Do you mean s2=-t2+x2+y2+z2 ? The OP wasn't talking about the interval. He was talking about the relationship between time dilation and velocity.

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