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1 = v^2 + t^2? and look at spacetime as velocity as x axis, time as y axis.

 
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Jan12-12, 06:45 PM   #1
 

1 = v^2 + t^2? and look at spacetime as velocity as x axis, time as y axis.


I am not so sure how to explain this. But when looking at sqrt( 1 - v^2/c^2 ) for time dilation. It seems to follow that you may be able to think about it as 1 = v^2 + t^2 if look at v as fraction of c, and t as the amount a clock will be dilated.

Then you could think about it in your frame of reference that all objects are moving at 1 through spacetime. If the velocity of an object gets larger then that just means that the t gets smaller.
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Jan12-12, 08:08 PM   #2
 
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You explained it very well. The equation you derived is for the reciprocal of gamma, the time dilation factor. It plots as a circle. See this post:
http://physicsforums.com/showpost.ph...81&postcount=6
Jan13-12, 09:34 AM   #3
 
I think it's more like sqrt(x^2 + y^2 + z^2 + t^2) = 1
4 dimensional law of pythagoras, using space and time.

next step is using this to understand / work out a twin paradox :)
Jan13-12, 10:12 AM   #4
 

1 = v^2 + t^2? and look at spacetime as velocity as x axis, time as y axis.


that should be a - t^2 right?
Jan13-12, 03:08 PM   #5
 
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Quote by HotBuffet View Post
I think it's more like sqrt(x^2 + y^2 + z^2 + t^2) = 1
4 dimensional law of pythagoras, using space and time.

next step is using this to understand / work out a twin paradox :)
Do you mean s2=-t2+x2+y2+z2 ? The OP wasn't talking about the interval. He was talking about the relationship between time dilation and velocity.
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