1 = v^2 + t^2? and look at spacetime as velocity as x axis, time as y axis.


by darkhorror
Tags: axis, spacetime, time, velocity
darkhorror
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#1
Jan12-12, 06:45 PM
P: 141
I am not so sure how to explain this. But when looking at sqrt( 1 - v^2/c^2 ) for time dilation. It seems to follow that you may be able to think about it as 1 = v^2 + t^2 if look at v as fraction of c, and t as the amount a clock will be dilated.

Then you could think about it in your frame of reference that all objects are moving at 1 through spacetime. If the velocity of an object gets larger then that just means that the t gets smaller.
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ghwellsjr
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#2
Jan12-12, 08:08 PM
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You explained it very well. The equation you derived is for the reciprocal of gamma, the time dilation factor. It plots as a circle. See this post:
http://physicsforums.com/showpost.ph...81&postcount=6
HotBuffet
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#3
Jan13-12, 09:34 AM
P: 4
I think it's more like sqrt(x^2 + y^2 + z^2 + t^2) = 1
4 dimensional law of pythagoras, using space and time.

next step is using this to understand / work out a twin paradox :)

jedishrfu
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#4
Jan13-12, 10:12 AM
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1 = v^2 + t^2? and look at spacetime as velocity as x axis, time as y axis.


that should be a - t^2 right?
elfmotat
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#5
Jan13-12, 03:08 PM
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Quote Quote by HotBuffet View Post
I think it's more like sqrt(x^2 + y^2 + z^2 + t^2) = 1
4 dimensional law of pythagoras, using space and time.

next step is using this to understand / work out a twin paradox :)
Do you mean s2=-t2+x2+y2+z2 ? The OP wasn't talking about the interval. He was talking about the relationship between time dilation and velocity.


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