Area under acceleration-time graph?

  • Thread starter Thread starter tahayassen
  • Start date Start date
  • Tags Tags
    Area Graph
AI Thread Summary
The area under an acceleration-time graph represents the change in velocity over a specified time interval. It is calculated as the difference between the instantaneous velocity at the final time and the initial velocity at the starting time. Clarification is made that the term "initial velocity" refers to the velocity at the beginning of the time interval being analyzed. This emphasizes the importance of defining the time values when interpreting the graph. Understanding this concept is crucial for analyzing motion in physics.
tahayassen
Messages
269
Reaction score
1

Homework Statement



What does the area under an acceleration-time graph give?

Homework Equations





The Attempt at a Solution



Instantaneous velocity.
 
Physics news on Phys.org
hi tahayassen! :smile:
tahayassen said:
What does the area under an acceleration-time graph give?
…
Instantaneous velocity.

strictly, instantaneous velocity minus initial velocity :wink:
 
tiny-tim said:
hi tahayassen! :smile:


strictly, instantaneous velocity minus initial velocity :wink:

Oh, because it gives you the change in velocity. Opps!
 
Actually, which initial velocity are we talking about? The initial velocity of that instant?
 
"the area under" must mean "between two values of t" …

one value is the present time, the other value is what we usually call the initial time :wink:
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Graphs of RC Circuit Responses
Replies
3
Views
940
Understanding Distance and Displacement on Velocity-Time Graphs
Replies
25
Views
2K
Finding the change in velocity from an acceleration vs time graph
Replies
1
Views
3K
Steps for converting one type of graph to the other?
Replies
4
Views
1K
Distance Velocity Graph: What Does the Area Represent?
Replies
2
Views
1K
Why would this be accelerating positively?
Replies
6
Views
963
Momentum and Impulse Problem with a Ball bouncing off a Wall
Replies
9
Views
3K
Area under a frequency vs wavelength graph?
Replies
9
Views
4K
Calculating Area Under a Graph with Units in Gravity-Free Space
Replies
7
Views
1K
How Does Impulse Relate to Momentum Change in Physics Problems?
Replies
7
Views
2K

Hot Threads

Recent Insights

Back
Top