Instantaneous Velocity from the graph

AI Thread Summary
The discussion centers on calculating instantaneous velocity from a distance-time graph, specifically at time intervals like 1.1s, 7.4s, and 2.7s. It emphasizes that on a graph with straight lines, the slope represents both average and instantaneous velocity, as there are no curves to consider. The participants clarify that the slope at any point, such as 1.1 seconds, is equivalent to the slope at nearby points, reinforcing that the lines intersect at rational values. The confusion about tangents is addressed, noting that for straight lines, the tangent line is essentially the same as the line itself. Overall, the conclusion is that for linear graphs, the instantaneous velocity can be determined directly from the slope of the line.
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Homework Statement



The problem is finding the instantaneous velocity during certain time intervals from the graph.
p2-03.gif


Examples of time intervals: 1.1s, 7.4s, 2.7s

Homework Equations



I know this is the formula for finding the instantaneous velocity

lim Δv=(Δx/Δt)
t->0

The Attempt at a Solution



I tried locating the points on the curve, by taking two obvious points like 1 on the x and 4 on the y and then making a cross multiplication to find the y in terms of 1.1 and then dividing by the T, since I do not think drawing a tangent to the point is possible here. So, should I use the equation somehow? I made several attempts but they all turned out to be incorrect.
 
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According to your graph, there are no "curves", but only straight lines. Recall that on a distance-time graph, the slope is the velocity. The lines' slopes are easy to calculate because they intersect on reasonable numbers.

So, the slope at 1.1 sec would be equal to the slope at 1 sec or any time within 0-2 seconds.

Also, at x=1, y does not equal 4, but actually equals 5.
 
Shootertrex said:
According to your graph, there are no "curves", but only straight lines. Recall that on a distance-time graph, the slope is the velocity. The lines' slopes are easy to calculate because they intersect on reasonable numbers.

So, the slope at 1.1 sec would be equal to the slope at 1 sec or any time within 0-2 seconds.

Also, at x=1, y does not equal 4, but actually equals 5.

But isn't the average velocity different than the instantaneous one? Like, I know the slope can represent the average velocity, but is that true on this graph for instantaneous velocity too because it's not a curve?
 
Instantaneous velocity is the slope of the line tangent to a point on a curve. Is there really a way to make a line that will be tangent to another line? Not really. Let's say that you can. This 'tangent' line have the same slope as the line it is tangent to, and is actually the same line.

Lets say that f(x)=4x will be the equation that illustrates the distance of an object. Velocity is the change in distance over the change in time. The change in distance for this function is the slope of the line. Therefore the slope of this line will equal the velocity, both average and instantaneous.
 
Yes, that is true. Thank you VERY much for that ^^
 
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